syntax error on `If` line

My code:

#!/usr/bin/env python

def Runaaall(a开发者_高级运维aa):
  Objects9(1.0, 2.0)

def Objects9(aaa1, aaa2):
  If aaa2 != 0: print aaa1 / aaa2

The error I receive:

$ python test2.py 
  File "test2.py", line 7
    If aaa2 != 0: print aaa1 / aaa2
          ^
SyntaxError: invalid syntax

I'm at a loss to why this error is happening.

if must be written in lower case.

Furthermore,

• Write function names in lower case (see PEP 8, the Python style guide).
• Write the body of an if-clause on a separate line.
• Though in this case you'll probably not run into trouble, be careful with comparing floats for equality.

• Since you've just started learning Python, you may want to get acquainted with writing parentheses around the arguments to print, since from Python 3 onwards, print is a function, not a keyword.
  To enforce this syntax in Python 2.6, you can put this at the top of your file:

  from __future__ import print_function
  

  Demonstration:

  >>> print 'test'
  test
  >>> from __future__ import print_function
  >>> print 'test'
    File "<stdin>", line 1
      print 'test'
                 ^
  SyntaxError: invalid syntax
  >>> print('test')
  test
  

  For more on __future__ imports, see the documentation.

It's the capital 'I' on "If". Change it to "if" and it will work.

How about

def Objects9(aaa1, aaa2):
  if aaa2 != 0: print aaa1 / aaa2

Python keywords are case sensitive, so you must write 'if' instead of 'If', 'for' instead of 'fOR', et cetera.