Print elements of a list to a .csv file

I am reading in a csv file and dealing with each line as a list. At the end, I'd like to reprint to a .csv file, but the lines aren't necessar开发者_如何学运维ily even. I obviously cannot just go "print row", since this will print it as a list. How can I print it in .csv format?

Read manual, there's a CSV writer method (with example too). Don't print the data, store them and then write them into CSV file

http://docs.python.org/library/csv.html#csv.writer

Assuming that "row" contains a list of strings, you could try using

print ",".join(row)

Though it looks like your question was more towards writing to a csv file rather than printing it to standard output, here an example to do the latter using StringIO:

import StringIO
import csv

a_list_from_csv_file = [['for', 'bar'], [1, 2]]
out_fd = StringIO.StringIO()
writer = csv.writer(out_fd, delimiter='|')
for row in a_list_from_csv_file:
    writer.writerow(row)
print out_fd.getvalue()

Like this you can use the different delimiters or escape characters as used by the csv you are reading.

What do you mean by "the lines aren't necessarily even"? Are you using a homebrew CSV parser or are you using the csv module?

If the former and there's nothing special you need to escape, you could try something like

print ",".join([ '"' + x.replace('"', '""') + '"' for x in row])

If you don't want ""s around each field, maybe make a function like escape_field() that checks if it needs to be wrapped in double quotes and/or escaped.