Zip function for shell scripts

I'm trying to write a shell script that will make several targets int开发者_高级运维o several different paths. I'll pass in a space-separated list of paths and a space-separated list of targets, and the script will make DESTDIR=$path $target for each pair of paths and targets. In Python, my script would look something like this:

for path, target in zip(paths, targets):
    exec_shell_command('make DESTDIR=' + path + ' ' + target)

However, this is my current shell script:

#! /bin/bash

packages=$1
targets=$2
target=

set_target_number () {
    number=$1
    counter=0
    for temp_target in $targets; do
        if [[ $counter -eq $number ]]; then
            target=$temp_target
        fi
        counter=`expr $counter + 1`
    done 
}

package_num=0
for package in $packages; do
    package_fs="debian/tmp/$package"
    set_target_number $package_num
    echo "mkdir -p $package_fs"
    echo "make DESTDIR=$package_fs $target"
    package_num=`expr $package_num + 1`
done

Is there a Unix tool equivalent to Python's zip function or an easier way to retrieve an element from a space-separated list by its index? Thanks.

Use an array:

#!/bin/bash
packages=($1)
targets=($2)
if (("${#packages[@]}" != "${#targets[@]}"))
then
    echo 'Number of packages and number of targets differ' >&2
    exit 1
fi
for index in "${!packages[@]}"
do
    package="${packages[$index]}"
    target="${targets[$index]}"
    package_fs="debian/tmp/$package"
    mkdir -p "$package_fs"
    make "DESTDIR=$package_fs" "$target"
done

Here is the solution

paste -d ' ' paths targets | sed 's/^/make DESTDIR=/' | sh

paste is equivalent of zip in shell. sed is used to prepend the make command (using regex) and result is passed to sh to execute

There's no way to do that in bash. You'll need to create two arrays from the input and then iterate through a counter using the values from each.