dual click problem
i've made an image slide show which works with either a next button, or if you click on the right or left of the screen it shows the next slide.
problem is when i click the next button the click bind also fires which means it move forward 2 slides.
How can i get the click bind to ignore the click if th next button is clicked?!
$(opts.next).click(function(){
nextSlide();
});
function nextSlide() {
$slides.eq(currentSlide).fadeOut(opts.speed)
currentSlide++;
(currentSlide==totalSlides ? currentSlide=0 : false);
updateSlideSHow()
}
function previousSlide() {
$slides.eq(currentSlide).fadeOut(opts.speed)
currentSlide--;
(currentSlide<0 ? currentSlide=(totalSlides-1) : false);
updateSlideSHow()
}
$(this).bind('mouseup',function(e){
var ww = $(window).width();
(e.pageX < (ww/2) ? previousSlide开发者_运维知识库() : nextSlide());
//alert(e.pageX+"<"+ww);
});
any help appreciated!
Where are the "next" buttons according to the DOM? Is the screen element, where I can click and go to the next slide, the parent element of these buttons?
The reason I ask is if they are that way, for instance:
<div id='screen'>
<img id='nextBtn' />
</div>
I'm not 100% but I would think if you tried clicking on the image button that the div would also register as a click, since its the parent element. Instead you could try this:
<div id='screen'></div>
<img id='nextBtn' />
And position the screen element absolutely and behind the image element.
ok - basically got the click to check for a URL before executing;
$(document).bind('click',function(e){
var ww = $(window).width();
if(!$(this).attr('href')) $()(e.pageX < (ww/2) ? previousSlide() : nextSlide());
//alert(e.pageX+"<"+ww);
});
Just curious, but if clicking the button would go to next through the click event, why not leave a button that does nothing there?
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