deleting all the file of certain size

i have bunch of log files and I have to delete the files of some small sizes, w开发者_StackOverflow中文版hich were erroneous files that got created. ( 63bytes ). I have to copy only those files which have data in it .

Shell (linux);

find . -type f -size 63c -delete

Will traverse subdirectories (unless you tell it otherwise)

Since you tagged your question with "python" here is how you could do this in that language:

target_size = 63
import os
for dirpath, dirs, files in os.walk('.'):
    for file in files: 
        path = os.path.join(dirpath, file)
        if os.stat(path).st_size == target_size:
            os.remove(path)

The Perl one liner is

perl -e 'unlink grep {-s == 63} glob "*"'

Although, it is always a good idea to test what it would do before running it:

perl -le 'print for grep {-s == 63} glob "*"'

If you want to walk an entire directory tree, you will need a different versions:

#find all files in the current hierarchy that are 63 bytes long.
perl -MFile::Find=find -le 'find sub {print $File::Find::name if -s == 63}, "."'

#delete all files in the current hierarchy that 63 bytes long
perl -MFile::Find=find -e 'find sub {unlink if -s == 63}, "."'

I am using need $File::Find::name in the finding version so you get the whole path, the unlinking version doesn't need it because File::Find changes directory into the each target directory and sets $_ to be the file name (which is how -s and unlink get the filename). You may also want to look up grep and glob