How do I get a GtkTreePath or GtkTreeIter to the last row in a GtkTreeModel?
I want to get a GtkTreePath or GtkTreeIter to the last row in a GtkTreeModel, bu开发者_开发技巧t GtkTreeModel does not have a function for that.
I'll be happy with answers and examples in either C, or Python, or both ;).
You should be able to go through a GtkTreePath, a bit of a hack maybe but still within the API:
GtkTreePath *path;
GtkTreeIter iter;
/* With NULL as iter, we get the number of toplevel nodes. */
gint rows = gtk_tree_model_iter_n_children(GTK_TREE_MODEL(model), NULL);
/* Now get a path from the index. */
path = gtk_tree_path_new_from_indices(rows - 1, -1);
/* Ask the model for an iter to the node identified by the path. */
gtk_tree_model_get_iter(GTK_TREE_MODEL(model), &iter, path);
/* Drop the path, we're done with it, iter is final output. */
gtk_tree_path_free(path);
Note: I haven't tested the above as I wrote it, but I'm pretty sure I've done something very similar in real code.
Even though unwind's answer was correct and enough to put me on the right track, I thought I'd add my final solutions just for completeness' sake:
Python:
def model_get_iter_last( model, parent=None ):
"""Returns a gtk.TreeIter to the last row or None if there aren't any rows.
If parent is None, returns a gtk.TreeIter to the last root row."""
n = model.iter_n_children( parent )
return n and model.iter_nth_child( parent, n - 1 )
C:
/**
* Set itr_last to last item of parent if parent has any rows.
* If parent is NULL, set itr_last to last root row.
* Returns TRUE if itr_last could be set, otherwise FALSE.
*/
gboolean model_get_iter_last( GtkTreeModel *model,
GtkTreeIter *itr_last,
GtkTreeIter *parent )
{
gboolean success;
gint n;
if ( n = gtk_tree_model_iter_n_children( model, parent ) ) {
success = gtk_tree_model_iter_nth_child( model, itr_last, parent, n - 1 );
}
else {
itr_last = NULL;
success = FALSE;
}
return success;
}
Here is how I do it currently, but it seems clumsy...
C example:
void get_iter_last( GtkTreeModel *mdl, GtkTreeIter *itr )
{
GtkTreeIter i;
if ( gtk_tree_model_get_iter_first( mdl, &i ) ) {
while ( gtk_tree_model_iter_next( mdl, &i ) ) {
*itr = i;
}
}
}
Python example:
def get_iter_last( mdl ):
itr = mdl.get_iter_first()
last = None
while itr:
last = itr
itr = mdl.iter_next( itr )
return last
Thanks for all previous answers, however I believe that final solution should include that TreeModel (with TreeStore) can store items with many levels of nesting (eg. path (2,0,4,2)). Solution posted by 'fresh' didn't worked for me, as I needed a function that will properly traverse thru all of the last children, until it really finds last row. Below is my final solution:
def get_last_iter (self, model):
n = model.iter_n_children (None)
# list empty
if n == 0:
return None
else:
iter = model.iter_nth_child (None, n - 1)
n = model.iter_n_children (iter)
# last top-level item has no children, so select that last item
if n == 0:
return iter
else:
# traverse thru every last child
while 1:
iter = model.iter_nth_child (iter, n - 1)
n = model.iter_n_children (iter)
if n == 0:
return iter
Or even shorter form:
def get_last_iter (self, model):
iter = None
n = 0
while 1:
iter = model.iter_nth_child (iter, n - 1)
n = model.iter_n_children (iter)
if n == 0:
return iter
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