Converting a list to a string [duplicate]
I have extracted some data from a file and want to write it to a second file. But my program is returning the error:
sequence item 1: expected string, list found
This appears to be happening because write()
wants a string but it is receiving a list.
So, with respect to this code, how can I convert the list buffer
to a string so that I can save the contents of buffer
to file2
开发者_如何学C?
file = open('file1.txt','r')
file2 = open('file2.txt','w')
buffer = []
rec = file.readlines()
for line in rec :
field = line.split()
term1 = field[0]
buffer.append(term1)
term2 = field[1]
buffer.append[term2]
file2.write(buffer) # <== error
file.close()
file2.close()
Try str.join
:
file2.write(' '.join(buffer))
Documentation says:
Return a string which is the concatenation of the strings in the iterable iterable. The separator between elements is the string providing this method.
''.join(buffer)
file2.write( str(buffer) )
Explanation:
str(anything)
will convert any python object into its string representation. Similar to the output you get if you do print(anything)
, but as a string.
NOTE: This probably isn't what OP wants, as it has no control on how the elements of buffer
are concatenated -- it will put ,
between each one -- but it may be useful to someone else.
buffer=['a','b','c']
obj=str(buffer)
obj[1:len(obj)-1]
will give "'a','b','c'" as output
file2.write(','.join(buffer))
Method 1:
import functools
file2.write(functools.reduce((lambda x,y:x+y), buffer))
Method 2:
import functools, operator
file2.write(functools.reduce(operator.add, buffer))
Method 3:
file2.write(''.join(buffer))
# it handy if it used for output list
list = [1, 2, 3]
stringRepr = str(list)
# print(stringRepr)
# '[1, 2, 3]'
From the official Python Programming FAQ for Python 3.6.4:
What is the most efficient way to concatenate many strings together?
str
andbytes
objects are immutable, therefore concatenating many strings together is inefficient as each concatenation creates a new object. In the general case, the total runtime cost is quadratic in the total string length.To accumulate many str objects, the recommended idiom is to place them into a list and call
str.join()
at the end:
chunks = []
for s in my_strings:
chunks.append(s)
result = ''.join(chunks)
(another reasonably efficient idiom is to use
io.StringIO
)To accumulate many bytes objects, the recommended idiom is to extend a
bytearray
object using in-place concatenation (the+=
operator):
result = bytearray()
for b in my_bytes_objects:
result += b
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