开发者

The case of the sneaky backslash - Regex

I'm missing something very obvious here, but I just cant s开发者_JAVA技巧ee it.

I've got:

string input = @"999\abc.txt";
string pattern = @"\\(.*)";
string output = Regex.Match(input,pattern).ToString();
Console.WriteLine(output);

My result is:

\abc.txt

I don't want the slash and cant figure out why it's sneaking into the output. I tried flipping the pattern, and the slash winds up in the output again:

string pattern = @"^(.*)\\";

and get:

999\

Strange. The result is fine in Osherove's Regulator. Any thoughts?

Thanks.


The Match is the entire match; you want the first group;

string output = Regex.Match(input,pattern).Groups[1].Value;

(from memory; may vary slightly)


Use Groups to get only the group, not the entire match:

string output = Regex.Match(input, pattern).Groups[1].Value;


You need to look at the results in Groups, not the entire matched text.

http://msdn.microsoft.com/en-us/library/system.text.regularexpressions.match.groups(v=VS.71).aspx


As an alternative to Marc's answer, you can use a zero-width positive lookbehind assertion in your pattern :

string pattern = @"(?<=\\)(.*)";

This will match "\" but exclude it from the capture


You could try the match prefix/postfix but exclude options.

Match everything after the first slash /

(?<=\\)(.*)$

Match everything after the last slash /

(?<=\\)([^\\]*)$

Match everything before the last slash /

^(.*)(?=\\)

BTW, download Expresso for testing regular expressions, total life-saver.

0

上一篇:

下一篇:

精彩评论

暂无评论...
验证码 换一张
取 消

最新问答

问答排行榜