Python: Seeing all files in Hex

I am writing a python script which looks at c开发者_StackOverflowommon computer files and examines them for similar bytes, words, double word's. Though I need/want to see the files in Hex, ande cannot really seem to get python to open a simple file in python. I have tried codecs.open with hex as the encoding, but when I operate on the file descriptor it always spits back

      File "main.py", line 41, in <module>
    main()
  File "main.py", line 38, in main
    process_file(sys.argv[1])
  File "main.py", line 27, in process_file
    seeker(line.rstrip("\n"))
  File "main.py", line 15, in seeker
    for unit in f.read(2):
  File "/usr/lib/python2.6/codecs.py", line 666, in read
    return self.reader.read(size)
  File "/usr/lib/python2.6/codecs.py", line 472, in read
    newchars, decodedbytes = self.decode(data, self.errors)
  File "/usr/lib/python2.6/encodings/hex_codec.py", line 50, in decode
    return hex_decode(input,errors)
  File "/usr/lib/python2.6/encodings/hex_codec.py", line 42, in hex_decode
    output = binascii.a2b_hex(input)
TypeError: Non-hexadecimal digit found





def seeker(_file):
 f = codecs.open(_file, "rb", "hex")
 for LINE in f.read():
      print LINE
 f.close()

I really just want to see files, and operate on them as if it was in a hex editor like xxd. Also is it possible to read a file in increments of maybe a word at a time.

No this is not homework.

codecs.open(_file, "rb", "hex") is trying to decode the file's contents as being hex, which is why it's failing on you.

Considering your other "word at a time" target (I assume you mean "computer word", i.e. 32 bits?), you'll be better off encapsulating the open file into a class of your own. E.g.:

class HexFile(object):
    def __init__(self, fp, wordsize=4):
        self.fp = fp
        self.ws = wordsize
    def __iter__(self):
        while True:
            data = self.fp.read(self.ws)
            if not data: break
            yield data.encode('hex')

plus whatever other utility methods you'd find helpful, of course.

You can read a set number of bytes by passing an integer argument to read:

32bits = file.read(4)

You can seek to a position in the file using seek:

file.seek(100) # Seeks to byte 100

if this will be more clear... : def hexfile(file_path): fp=open(file_path) while True: data = fp.read(4) if not data: break print data.encode('hex')

file_path is something like "C:/somedir/filename.ext" it nice method btw it will work nicely for me. :)