How do I define functions using Racket macros?
I am trying to write a macro that defines a special class of data structure with associated functions.
I know this is possible; it is done multiple times in the core language itself.
As a specific example, how would I define the define-struct
macro in Scheme itself. It needs to create make-struct
, struct-<<field>>
, etc functions.
I tried开发者_JAVA技巧 doing this using define
, however, this only defines the function in the macro's lexical scope.
How can I actually define a function in a macro?
The key for an answer is datum->syntax
. The basic idea is that you want to take some random data and turn it into a syntax -- in this case, turn a symbol into an identifier. An identifier is basically a symbol with some lexical information that (very roughly) indicates how it is bound. Using datum->syntax
you can do exactly that: it expects an existing piece of syntax which is where it copies the binding from, and a datum (a symbol here) which is the value that is contained in the syntax wrapper.
Here's an example that demonstrates a define-struct
-like tool using this:
#lang scheme
;; implements a defstruct-like macro that uses association lists
(define-syntax (defstruct-lite stx)
(syntax-case stx ()
[(defstruct-lite name field ...)
(let ([make-id
(lambda (template . ids)
(let ([str (apply format template (map syntax->datum ids))])
(datum->syntax stx (string->symbol str))))])
(with-syntax ([make-name (make-id "make-~a" #'name)]
[name? (make-id "~a?" #'name)]
[(arg ...) (generate-temporaries #'(field ...))]
[(name-field ...)
(map (lambda (f) (make-id "~a-~a" #'name f))
(syntax->list #'(field ...)))])
#'(begin
(define (make-name arg ...) (list 'name (cons 'field arg) ...))
(define (name? x) (and (pair? x) (eq? 'name (car x))))
(define (name-field x)
(and (name? x) (cdr (assq 'field (cdr x)))))
...)))]))
And here's an example of using it:
(defstruct-lite point x y)
(point-y (make-point 1 2))
精彩评论