read subprocess stdout line by line

My python script uses subprocess to call a linux utility that is very noisy. I want to store all of the output to a log file and show some of it to the user. I thought the following would work, but the output doesn't show up in my application until the utility has produced a significant amount of output.

#fake_utility.py, just generates lots of output over time
import time
i = 0
while True:
   print hex(i)*512
   i += 1
   time.sleep(0.5)

#filters output
import subprocess
proc = subprocess.Popen(['python','fake_utility.py'],stdout=subprocess.PIPE)
for line in proc.stdout:
   #the real code does filtering here
   print "test:", line.rstrip()

The behavior I really want is for the filter script to print each line as it is received from the subprocess. Sorta like what tee does but with python code.

What am I missing? Is this even possible?

Update:

If a sys.stdout.flush() is added to fake_utility.py, the code has the desired behavior in python 3.1. I'm using python 2.6. You would think that using proc.stdout.xreadlines() would work the same as py3k, but it doesn't.

Update 2:

Here 开发者_开发技巧is the minimal working code.

#fake_utility.py, just generates lots of output over time
import sys, time
for i in range(10):
   print i
   sys.stdout.flush()
   time.sleep(0.5)

#display out put line by line
import subprocess
proc = subprocess.Popen(['python','fake_utility.py'],stdout=subprocess.PIPE)
#works in python 3.0+
#for line in proc.stdout:
for line in iter(proc.stdout.readline,''):
   print line.rstrip()

I think the problem is with the statement for line in proc.stdout, which reads the entire input before iterating over it. The solution is to use readline() instead:

#filters output
import subprocess
proc = subprocess.Popen(['python','fake_utility.py'],stdout=subprocess.PIPE)
while True:
  line = proc.stdout.readline()
  if not line:
    break
  #the real code does filtering here
  print "test:", line.rstrip()

Of course you still have to deal with the subprocess' buffering.

Note: according to the documentation the solution with an iterator should be equivalent to using readline(), except for the read-ahead buffer, but (or exactly because of this) the proposed change did produce different results for me (Python 2.5 on Windows XP).

Bit late to the party, but was surprised not to see what I think is the simplest solution here:

import io
import subprocess

proc = subprocess.Popen(["prog", "arg"], stdout=subprocess.PIPE)
for line in io.TextIOWrapper(proc.stdout, encoding="utf-8"):  # or another encoding
    # do something with line

(This requires Python 3.)

Indeed, if you sorted out the iterator then buffering could now be your problem. You could tell the python in the sub-process not to buffer its output.

proc = subprocess.Popen(['python','fake_utility.py'],stdout=subprocess.PIPE)

becomes

proc = subprocess.Popen(['python','-u', 'fake_utility.py'],stdout=subprocess.PIPE)

I have needed this when calling python from within python.

You want to pass these extra parameters to subprocess.Popen:

bufsize=1, universal_newlines=True

Then you can iterate as in your example. (Tested with Python 3.5)

A function that allows iterating over both stdout and stderr concurrently, in realtime, line by line

In case you need to get the output stream for both stdout and stderr at the same time, you can use the following function.

The function uses Queues to merge both Popen pipes into a single iterator.

Here we create the function read_popen_pipes():

from queue import Queue, Empty
from concurrent.futures import ThreadPoolExecutor


def enqueue_output(file, queue):
    for line in iter(file.readline, ''):
        queue.put(line)
    file.close()


def read_popen_pipes(p):

    with ThreadPoolExecutor(2) as pool:
        q_stdout, q_stderr = Queue(), Queue()

        pool.submit(enqueue_output, p.stdout, q_stdout)
        pool.submit(enqueue_output, p.stderr, q_stderr)

        while True:

            if p.poll() is not None and q_stdout.empty() and q_stderr.empty():
                break

            out_line = err_line = ''

            try:
                out_line = q_stdout.get_nowait()
            except Empty:
                pass
            try:
                err_line = q_stderr.get_nowait()
            except Empty:
                pass

            yield (out_line, err_line)

read_popen_pipes() in use:

import subprocess as sp


with sp.Popen(my_cmd, stdout=sp.PIPE, stderr=sp.PIPE, text=True) as p:

    for out_line, err_line in read_popen_pipes(p):

        # Do stuff with each line, e.g.:
        print(out_line, end='')
        print(err_line, end='')

    return p.poll() # return status-code

You can also read lines w/o loop. Works in python3.6.

import os
import subprocess

process = subprocess.Popen(command, stdout=subprocess.PIPE)
list_of_byte_strings = process.stdout.readlines()

I tried this with python3 and it worked, source

When you use popen to spawn the new thread, you tell the operating system to PIPE the stdout of the child processes so the parent process can read it and here, stderr is copied to the stderr of the parent process.

in output_reader we read each line of stdout of the child process by wrapping it in an iterator that populates line by line output from the child process whenever a new line is ready.

def output_reader(proc):
    for line in iter(proc.stdout.readline, b''):
        print('got line: {0}'.format(line.decode('utf-8')), end='')


def main():
    proc = subprocess.Popen(['python', 'fake_utility.py'],
                            stdout=subprocess.PIPE,
                            stderr=subprocess.STDOUT)

    t = threading.Thread(target=output_reader, args=(proc,))
    t.start()

    try:
        time.sleep(0.2)
        import time
        i = 0
    
        while True:
        print (hex(i)*512)
        i += 1
        time.sleep(0.5)
    finally:
        proc.terminate()
        try:
            proc.wait(timeout=0.2)
            print('== subprocess exited with rc =', proc.returncode)
        except subprocess.TimeoutExpired:
            print('subprocess did not terminate in time')
    t.join()

The following modification of Rômulo's answer works for me on Python 2 and 3 (2.7.12 and 3.6.1):

import os
import subprocess

process = subprocess.Popen(command, stdout=subprocess.PIPE)
while True:
  line = process.stdout.readline()
  if line != '':
    os.write(1, line)
  else:
    break

Pythont 3.5 added the methods run() and call() to the subprocess module, both returning a CompletedProcess object. With this you are fine using proc.stdout.splitlines():

proc = subprocess.run( comman, shell=True, capture_output=True, text=True, check=True )
for line in proc.stdout.splitlines():
   print "stdout:", line

See also How to Execute Shell Commands in Python Using the Subprocess Run Method

I was having a problem with the arg list of Popen to update servers, the following code resolves this a bit.

import getpass
from subprocess import Popen, PIPE

username = 'user1'
ip = '127.0.0.1'

print ('What is the password?')
password = getpass.getpass()
cmd1 = f"""sshpass -p {password} ssh {username}@{ip}"""
cmd2 = f"""echo {password} | sudo -S apt update"""
cmd3 = " && "
cmd4 = f"""echo {password} | sudo -S apt upgrade -y"""
cmd5 = " && "
cmd6 = "exit"
commands = [cmd1, cmd2, cmd3, cmd4, cmd5, cmd6]

command = " ".join(commands)

cmd = command.split()

with Popen(cmd, stdout=PIPE, bufsize=1, universal_newlines=True) as p:
    for line in p.stdout:
        print(line, end='')

And to run the update on a local computer, the following code example does this.

import getpass
from subprocess import Popen, PIPE

print ('What is the password?')
password = getpass.getpass()

cmd1_local = f"""apt update"""
cmd2_local = f"""apt upgrade -y"""
commands = [cmd1_local, cmd2_local]

with Popen(['echo', password], stdout=PIPE) as auth:
    for cmd in commands:
        cmd = cmd.split()
        with Popen(['sudo','-S'] + cmd, stdin=auth.stdout, stdout=PIPE, bufsize=1, universal_newlines=True) as p:
            for line in p.stdout:
                print(line, end='')