Encoding gives "'ascii' codec can't encode character … ordinal not in range(128)"
I am working through the Django RSS reader project here.
The RSS feed will read something like "OKLAHOMA CITY (AP) — James Harden let". The RSS feed's encoding reads encoding="UTF-8" so I believe I am passing utf-8 to markdown in the code snippet below. The em 开发者_开发问答dash is where it chokes.
I get the Django error of "'ascii' codec can't encode character u'\u2014' in position 109: ordinal not in range(128)" which is an UnicodeEncodeError. In the variables being passed I see "OKLAHOMA CITY (AP) \u2014 James Harden". The code line that is not working is:
content = content.encode(parsed_feed.encoding, "xmlcharrefreplace")
I am using markdown 2.0, django 1.1, and python 2.4.
What is the magic sequence of encoding and decoding that I need to do to make this work?
(In response to Prometheus' request. I agree the formatting helps)
So in views I add a smart_unicode line above the parsed_feed encoding line...
content = smart_unicode(content, encoding='utf-8', strings_only=False, errors='strict')
content = content = content.encode(parsed_feed.encoding, "xmlcharrefreplace")
This pushes the problem to my models.py for me where I have
def save(self, force_insert=False, force_update=False):
if self.excerpt:
self.excerpt_html = markdown(self.excerpt)
# super save after this
If I change the save method to have...
def save(self, force_insert=False, force_update=False):
if self.excerpt:
encoded_excerpt_html = (self.excerpt).encode('utf-8')
self.excerpt_html = markdown(encoded_excerpt_html)
I get the error "'ascii' codec can't decode byte 0xe2 in position 141: ordinal not in range(128)" because now it reads "\xe2\x80\x94" where the em dash was
If the data that you are receiving is, in fact, encoded in UTF-8, then it should be a sequence of bytes -- a Python 'str' object, in Python 2.X
You can verify this with an assertion:
assert isinstance(content, str)
Once you know that that's true, you can move to the actual encoding. Python doesn't do transcoding -- directly from UTF-8 to ASCII, for instance. You need to first turn your sequence of bytes into a Unicode string, by decoding it:
unicode_content = content.decode('utf-8')
(If you can trust parsed_feed.encoding, then use that instead of the literal 'utf-8'. Either way, be prepared for errors.)
You can then take that string, and encode it in ASCII, substituting high characters with their XML entity equivalents:
xml_content = unicode_content.encode('ascii', 'xmlcharrefreplace')
The full method, then, would look somthing like this:
try:
content = content.decode(parsed_feed.encoding).encode('ascii', 'xmlcharrefreplace')
except UnicodeDecodeError:
# Couldn't decode the incoming string -- possibly not encoded in utf-8
# Do something here to report the error
Django provides a couple of useful functions for converting back and forth between Unicode and bytestrings:
from django.utils.encoding import smart_unicode, smart_str
I encountered this error during a write of a file name with zip file. The following failed
ZipFile.write(root+'/%s'%file, newRoot + '/%s'%file)
and the following worked
ZipFile.write(str(root+'/%s'%file), str(newRoot + '/%s'%file))
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