List<> own comparer
I have a List where element is:
struct element {
double priority;
int value;
}
How can I implement my own comparer which all开发者_开发问答ow me sort List by priority ? I try with SortredList... but it don't allow douplicated keys :(
Big thanks for help!
Assuming C# 3 or later:
var sorted = MyList.OrderBy(e => e.priority);
You can perform an in-place sort by using the Sort
overload that takes a Comparison<T>
delegate:
yourList.Sort((x, y) => x.priority.CompareTo(y.priority));
For older versions of C# you'll need to swap out the lambda for old-school delegate syntax:
yourList.Sort(
delegate(element x, element y) { return x.priority.CompareTo(y.priority); });
If you can't rely on C# 3 extensions or Lambdas then you can have your struct implement the IComparable interface, like so:
struct element : IComparable
{
double priority;
int value;
public element(int val, double prio)
{
priority = prio;
value = val;
}
#region IComparable Members
public int CompareTo(object obj)
{
// throws exception if type is wrong
element other = (element)obj;
return priority.CompareTo(other.priority);
}
#endregion
}
There are also a typesafe version of this interface, but the principle is the same
After you have that interface implemented on your struct or class, calling the Sort method on List<>
will "just work"
static void Main(string[] args)
{
Random r = new Random();
List<element> myList = new List<element>();
for (int i = 0; i < 10; i++)
myList.Add(new element(r.Next(), r.NextDouble()));
// List is now unsorted
myList.Sort();
// List is now sorted by priority
Console.ReadLine();
}
This depends on if you want to sort the list itself, or retrieve the values in sorted order (without changing the list).
To sort the list itself (supposing you have a List<element>
called elements
):
elements.Sort((x, y) => x.priority.CompareTo(y.priority));
// now elements is sorted
.NET 2.0 equivalent:
elements.Sort(
delegate(element x, element y) {
return x.priority.CompareTo(y.priority);
}
);
To get the values in sorted order:
var orderedElements = elements.OrderBy(x => x.priority);
// elements remains the same, but orderedElements will retrieve them in order
There's no LINQ equivalent in .NET 2.0, but you can write your own:
public static IEnumerable<T> OrderBy<T>(IEnumerable<T> source, Comparison<T> comparison) {
List<T> copy = new List<T>(source);
copy.Sort(comparison);
foreach (T item in copy)
yield return item;
}
Usage:
Comparison<element> compareByPriority = delegate(element x, element y) {
return x.priority.CompareTo(y.priority);
};
// unfortunately .NET 2.0 doesn't support extension methods, so this has to be
// expressed as a regular static method
IEnumerable<element> orderedElements = OrderBy(elements, compareByPriority);
If you want to sort the list itself without creating a new instance, you can implement IComparer, then call List.Sort with an instance of your implementation
public class ElementComparer : IComparer<element>
{
public int Compare(element x, element y)
{
throw new NotImplementedException();
}
}
精彩评论