Error in Process.Start() -- The system cannot find the file specified

开发者_如何学PythonI am using the following code to fire the iexplore process. This is done in a simple console app.

public static void StartIExplorer()
{
    var info = new ProcessStartInfo("iexplore");
    info.UseShellExecute = false;
    info.RedirectStandardInput = true;
    info.RedirectStandardOutput = true;
    info.RedirectStandardError = true;

    string password = "password";
    SecureString securePassword = new SecureString();

    for (int i = 0; i < password.Length; i++)
        securePassword.AppendChar(Convert.ToChar(password[i]));

    info.UserName = "userName";
    info.Password = securePassword;
    info.Domain = "domain";

    try
    {
        Process.Start(info);
    }
    catch (System.ComponentModel.Win32Exception ex)
    {
        Console.WriteLine(ex.Message);
    }
}

The above code is throwing the error The system cannot find the file specified. The same code when run without specifying the user credentials works fine. I am not sure why it is throwing this error.

Can someone please explain?

Try to replace your initialization code with:

ProcessStartInfo info 
    = new ProcessStartInfo(@"C:\Program Files\Internet Explorer\iexplore.exe");

Using non full filepath on Process.Start only works if the file is found in System32 folder.

You can't use a filename like iexplore by itself because the path to internet explorer isn't listed in the PATH environment variable for the system or user.

However any path entered into the PATH environment variable allows you to use just the file name to execute it.

System32 isn't special in this regard as any directory can be added to the PATH variable. Each path is simply delimited by a semi-colon.

For example I have c:\ffmpeg\bin\ and c:\nmap\bin\ in my path environment variable, so I can do things like new ProcessStartInfo("nmap", "-foo") or new ProcessStartInfo("ffplay", "-bar")

The actual PATH variable looks like this on my machine.

%SystemRoot%\system32;C:\FFPlay\bin;C:\nmap\bin;

As you can see you can use other system variables, such as %SystemRoot% to build and construct paths in the environment variable.

So - if you add a path like "%PROGRAMFILES%\Internet Explorer;" to your PATH variable you will be able to use ProcessStartInfo("iexplore");

If you don't want to alter your PATH then simply use a system variable such as %PROGRAMFILES% or %SystemRoot% and then expand it when needed in code. i.e.

string path = Environment.ExpandEnvironmentVariables(
       @"%PROGRAMFILES%\Internet Explorer\iexplore.exe");
var info = new ProcessStartInfo(path);

Also, if your PATH's dir is enclosed in quotes, it will work from the command prompt but you'll get the same error message

I.e. this causes an issue with Process.Start() not finding your exe:

PATH="C:\my program\bin";c:\windows\system32

Maybe it helps someone.

I had the same problem, but none of the solutions worked for me, because the message The system cannot find the file specified can be misleading in some special cases.

In my case, I use Notepad++ in combination with the registry redirect for notepad.exe. Unfortunately my path to Notepad++ in the registry was wrong.

So in fact the message The system cannot find the file specified was telling me, that it cannot find the application (Notepad++) associated with the file type(*.txt), not the file itself.

I know it's a bit old and although this question have accepted an answer, but I think its not quite answer.

Assume we want to run a process here C:\Program Files\SomeWhere\SomeProcess.exe.

One way could be to hard code absolute path:

new ProcessStartInfo(@"C:\Program Files\SomeWhere\SomeProcess.exe")

Another way (recommended one) is to use only process name:

new ProcessStartInfo("SomeProcess.exe")

The second way needs the process directory to be registered in Environment Variable Path variable. Make sure to add it in System Variables instead of Current User Variables, this allows your app to access this variable.

You can use the folowing to get the full path to your program like this:

Environment.CurrentDirectory