How to convert a Integer to a ByteString in Haskell
We'd like to serialize data in a specific binary format. We use Data.ByteString
s internally.
So, the question is: How to convert the different data types we use to a ByteString
. For String
we have no problem, we can use encodeLazyByteString UTF8 "string"
. But we'd also like to convert Integer
s to ByteString
s (big-endian).
Does anyone开发者_JAVA技巧 know how to do that and/or has any good tips using Haskell and binary formats?
Thanks!
A perfect job for Data.Binary:
Prelude> :m + Data.Binary
Prelude Data.Binary> encode (pi :: Double)
Chunk "\SOH\SOH\NUL\NUL\NUL\NUL\NUL\NUL\NUL\a\CAN-DT\251!\EM\255\255\255\255\255\255\255\205" Empty
Prelude Data.Binary> encode (42 :: Integer)
Chunk "\NUL\NUL\NUL\NUL*" Empty
to yield lazy bytestrings, which can of course be converted to strict ones. The cereal package provides much the same interface, but yields strict bytestrings only (so no infinite streaming of encodings).
For those, like me, looking for a function to convert an Int or Integer to a ByteString you can use: Data.ByteString.Char8.pack . show Even better if it compiles in your ghc you can use show from TextShow. I understand that this is not quite the OP was asking but people looking for the preceding may end up puzzled at this page due to its title.
Have a look at the binary package, or any of its non-lazy variants: cereal or binary-strict .
In all three cases, since you have a specific binary format, I'd ignore the type class Binary
defined in each, and instead focus on the Put
and Get
monads they define.
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