Python, next iteration of the loop over a loop

I need to get the next item of the first loop given certain condition, but the condition is in the inner loop. Is there a shorter way to do i开发者_开发技巧t than this? (test code)

    ok = 0
    for x in range(0,10):
        if ok == 1:
            ok = 0
            continue
        for y in range(0,20): 
            if y == 5:
                ok = 1
                continue

What about in this situation?

for attribute in object1.__dict__:
    object2 = self.getobject()
    if object2 is not None:
        for attribute2 in object2: 
            if attribute1 == attribute2:
                # Do something
                #Need the next item of the outer loop

The second example shows better my current situation. I dont want to post the original code because it's in spanish. object1 and object2 are 2 very different objects, one is of object-relational mapping nature and the other is a webcontrol. But 2 of their attributes have the same values in certain situations, and I need to jump to the next item of the outer loop.

Replace the continue in the inner loop with a break. What you want to do is to actually break out of the inner loop, so a continue there does the opposite of what you want.

ok = 0
for x in range(0,10):
    print "x=",x
    if ok == 1:
        ok = 0
        continue
    for y in range(0,20): 
        print "y=",y
        if y == 5:
            ok = 1
            break

You can always transform into a while loop:

flag = False
for x in range(0, 10):
    if x == 4: 
        flag = True
        continue

becomes

x = 0
while (x != 4) and x < 10:
    x += 1
flag = x < 10

Not necessary simpler, but nicer imho.

Your example code is equivalent to (that doesn't seem what you want):

for x in range(0, 10, 2):
    for y in range(20): 
        if y == 5:
           continue

To skip to the next item without using continue in the outer loop:

it = iter(range(10))
for x in it:
    for y in range(20):
        if y == 5:
           nextx = next(it)
           continue

So you're not after something like this? I'm assuming that you're looping through the keys to a dictionary, rather than the values, going by your example.

for i in range(len(object1.__dict__)):
  attribute1 = objects1.__dict__.keys()[i]
  object2 = self.getobject() # Huh?
  if object2 is not None:
    for j in range(len(object2.__dict__)):
      if attribute1 == object2.__dict__.keys()[j]:
        try:
          nextattribute1 = object1.__dict__.keys()[i+1]
        except IndexError:
          print "Ran out of attributes in object1"
          raise

It's not completely clear to me what you want, but if you're testing something for each item produced in the inner loop, any might be what you want (docs)

>>> def f(n):  return n % 2
... 
>>> for x in range(10):
...     print 'x=', x
...     if f(x):
...         if any([y == 8 for y in range(x+2,10)]):
...             print 'yes'
... 
x= 0
x= 1
yes
x= 2
x= 3
yes
x= 4
x= 5
yes
x= 6
x= 7
x= 8
x= 9