Reading path in templates [duplicate]

This question already has answers here: How to get the current URL within a Django template? (16 answers) Closed 6 years ago.

is there any way to read the path to the current pag开发者_JS百科e? For example, I am at www.example.com/foo/bar/ - and I want to read '/foo/bar/'. I have to do this in the template file without modifying views, and I have too many view files to edit each one.

Cheers.

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If you add django.core.context_processors.request to your TEMPLATE_CONTEXT_PROCESSORS setting, it will add the request variable to every template-rendering that uses a RequestContext (which is most of the built-in ones). This is the HTTPRequest object for the current request, the path attribute of which is the requested path. More information can be found in the docs.

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request.path

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I ended up using this but ran into a little hiccup along the way. Here's my solution path in the hopes that I save someone else some time.

At first I added this line to my settings.py file:

TEMPLATE_CONTEXT_PROCESSORS = ("django.core.context_processors.request",)

I found that it allowed me to access the request path from within a template which had been passed a RequestContext by using the template variable {{ request.path }}. However, it also disabled all the other context processors. To fix this I tried adding the defaults to the TEMPLATE_CONTEXT_PROCESSORS tuple. At first this failed because I had used the context processors for Django 1.2 (I have Django 1.1 installed). After fixing that problem I was left with the following settings file:

TEMPLATE_CONTEXT_PROCESSORS = ("django.core.context_processors.auth",
 "django.core.context_processors.debug",
 "django.core.context_processors.i18n",
 "django.core.context_processors.media",
 "django.core.context_processors.request",
 )