Python - Converting Hex to INT/CHAR
I am having some difficulty changing a hex to an int/char (char preferably). Via the website; http://home2.paulschou.net/tools/xlate/ I enter the hex of C0A80026 into the hex box, in the DEC / CHAR box it correctly outputs the IP I expected it to contain.
开发者_Go百科This data is being pulled from an external database and I am not aware how it is being saved so all I have to work with is the hex string itself.
I have tried using the binascii.unhexlify
function to see if I could decode it but I fear that I may not have a great enough understanding of hex to appreciate what I am doing.
Attemping to print just using an int() cast also has not produced the required results. I need some way to convert from that hex string (or one similar) to the original IP.
UPDATE: For anyone who comes across this in the future I modified the below answer slightly to provide an exact printout as an IP by using;
dec_output = str(int(hex_input[0:2], 16)) + "." + str(int(hex_input[2:4], 16)) + "." + str(int(hex_input[4:6], 16)) + "." + str(int(hex_input[6:8], 16))
If you want to get 4 separate numbers from this, then treat it as 4 separate numbers. You don't need binascii
.
hex_input = 'C0A80026'
dec_output = [
int(hex_input[0:2], 16), int(hex_input[2:4], 16),
int(hex_input[4:6], 16), int(hex_input[6:8], 16),
]
print dec_output # [192, 168, 0, 38]
This can be generalised, but I'll leave it as an exercise for you.
A simple way
>>> s = 'C0A80026'
>>> map(ord, s.decode('hex'))
[192, 168, 0, 38]
>>>
if you prefer list comprehensions
>>> [ord(c) for c in s.decode('hex')]
[192, 168, 0, 38]
>>>
You might also need the chr function:
chr(65) => 'A'
>>> htext='C0A80026'
>>> [int(htext[i:i+2],16) for i in range(0,len(htext),2)]
# [192, 168, 0, 38]
For converting hex-string to human readable string you can escape every HEX character like this:
>>> '\x68\x65\x6c\x6c\x6f'
'hello'
from string you can easily loop to INT list:
>>> hextoint = [ord(c) for c in '\x68\x65\x6c\x6c\x6f']
>>> _
[104, 101, 108, 108, 111]
Your example:
>>> [ord(c) for c in '\xC0\xA8\x00\x26']
[192, 168, 0, 38]
I hope it's what you expect:
hex_val = 0x42424242 # hexadecimal value
int_val = int(hex_val) # integer value
str_val = str(int_val) # string representation of integer value
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