Copy the contents of an ImageField to a new file path in Django
I have a Django model object that has a few normal attributes, and it has a ImageField for the logo. I want to write a method that'll copy this object to a new object. It's easy enough to instanciate the new object, then loop over all the attributes and copy from the old to new (e.g. new_object.name = old_object.name
). However if I do that with the logo field (i.e. new_object.logo = old_object.logo
), both new_object and old_object point to the same file on the harddisk. If you edit the old file, the logo for the new object will change.
What's the 开发者_如何学Gobest way to have a full/deep copy of the ImageField? I want it to have a different file name and to point to a different file on the disk, but it should have exactly the same content.
Why not create a function that is fun on the save signal which copies the image file to whereever you want, then creates a new object with a new image field?
models.py
class ObjectOne(models.Model):
logo = models.ImageField(...)
class ObjectTwo(models.Model):
logo = models.ImageField(...)
from django.db.models.signals import post_save
from signals import my_signal
post_save.connect(my_signal, dispatch_uid="001")
signals.py
from models. import ObjectOne, ObjectTwo
def my_signal(sender, instance, *args, **kwargs):
if sender is ObjectOne:
new_obj = ObjectTwo()
new_obj.logo.save("custom/path/new_filename.jpg",File(open(instance.image.url,"w"))
new_obj.save()
I haven't tested the image copying code but this is the general idea. There is more here:
Programmatically saving image to Django ImageField
Django: add image in an ImageField from image url
how to manually assign imagefield in Django
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