Filenames and paths trouble
The following example "walks" through a directory, prints the names of all the files, and calls itself recursively on 开发者_JS百科all the directories.
import os
def walk(dir):
for name in os.listdir(dir):
path = os.path.join(dir,name)
if os.path.isfile(path):
print path
else:
walk1(path)
os.path.join` takes a directory and a file name and joins them into a complete path.
My exercise: Modify walk so that instead of printing the names of the files, it returns a list of names.
Can someone explain what this function is doing per line? I have a good idea but when it gets to the line: else: walk(path)
, that throws me off since there is no explanation what that is doing. For this exercise, the only way I could think to change this to a list is by:
def walk1(dir):
res = []
for name in os.listdir(dir):
path = os.path.join(dir,name)
if os.path.isfile(path):
res.append(path)
else:
walk1(path)
return res
My output went from so many output lines to just a mere few. Did I do this correctly?
Here's an annotated version with a small fix to the recursion.
def walk1(dir):
res = []
# for all entries in the folder,
for name in os.listdir(dir):
# compute the path relative to `dir`
path = os.path.join(dir,name)
# include entries recursively.
if os.path.isfile(path):
# the path points to a file, save it.
res.append(path)
else:
# the path points to a directory, so we need
# to fetch the list of entries in there too.
res.extend(walk1(path))
# produce all entries at once.
return res
You need to add the result of your recursion to what you already have.
A small module I wrote, pathfinder, makes it easier (in my opinion anyway) to find paths.
from pathfinder import pathfind
paths = pathfind(a_dir, just_files=True)
It's just a layer on top of os.walk, but removes some of the confusion surrounding it.
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