get line of a predefined sentence that in a txt file line?

so i have this code:

for line in open('music.txt'):
    if '开发者_如何学运维file : "' in line:


        c = line.split('file : "')

        del c[0]

        d="".join(c)

        a=re.sub('"','',d)

        e=re.sub(',','',a)


        urls.append(e)  

Is there a way to do this but without a file?

Maybe you want something like that:

urls = [re.findall(r'file : "(.*)"', line)[0].replace(',', '')
        for line in file if 'file :' in line]

and it works on any file object or list.

For standard input, use file = sys.stdin

Example:

file = ['file : "test, 123, 456, abcde"', 
        'other line', 
        'file : "zzzzzzzzz"]

output:

['test 123 456 abcde', 'zzzzzzzzz']

If you want to read from standard input (for example, in a pipeline) then you can just write

import sys
for line in sys.stdin:

And the rest will work. (sys.stdin is an open file corresponding to standard input)

If you have the lines in a list, then you can just iterate across the list using the same code.