python socket object accept time out

Question: Is there some sort of time out or interrupt to the socket.accept() function in python?

Info:

I have a program that has a child thread bound to a port and constantly accepting and tending and passing them to a queue for the main thread. Right now I'm trying to get the child t开发者_Go百科hread to interrupt so it can deconstruct appropriately. I think it is possible for me to just simply stop the child thread and have the parent deconstruct the child, but there are other times where I want to be able to return early form accept so I just decided that would be the most useful approach.

So, is there a way that I can have a time out or cancel the accept method so the thread can return w/o having something connect to it first?

You can use settimeout() as in this example:

import socket

tcpServer = socket.socket(socket.AF_INET, socket.SOCK_STREAM) 
tcpServer.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1)
tcpServer.settimeout(0.2) # timeout for listening
tcpServer.bind(('0.0.0.0', 10000)) # IP and PORT
tcpServer.listen(1)

stopped = False
while not stopped:
  try: 
    (conn, (ip, port)) = tcpServer.accept() 
  except socket.timeout:
    pass
  except:
    raise
  else:
    # work with the connection, create a thread etc.
    ...

The loop will run until stopped is set to true and then exit after (at most) the timeout you have set. (In my application I pass the connection handle to a newly created thread and continue the loop in order to be able to accept further simultaneous connections.)

You can set the default timeout with

import socket
print socket.getdefaulttimeout()
socket.setdefaulttimeout(60)

AFAIK This will affect all the socket operation

Maybe settimeout() is what you're looking for.