how to move 2 circles on the screen independently of each other?
I've an app that paints 2 circles on the screen. once drawn I can move one of the circles around and place where i want. Is there a way to determin which circle I have touched so that I can move that particular circle? At the moment I can only move the circle at co-ords at centreX centreY.
public boolean onTouchEvent(MotionEvent ev) {
switch (ev.getAction()) {
case MotionEvent.ACTION_DOWN: {
if(xyFound == false) {
centreX = (int) ev.getX()-70;
centreY = (int) ev.getY()-70;
xyFound = true;
} else {
centreA = (int) ev.getX()-70;
centreB = (int) ev.getY()-70;
abFound = true;
bothCirclesInPlace = true;
invalidate();
}
}
case MotionEvent.ACTION_MO开发者_如何学JAVAVE: {
if(xyFound == false){
centreX = (int) ev.getX()-70;
centreY = (int) ev.getY()-70;
xyFound = true;
}else{
centreA = (int) ev.getX()-70;
centreB = (int) ev.getY()-70;
bothCirclesInPlace = true;
invalidate();
} break;
}
.
[update1]
@Override
public boolean onTouchEvent(MotionEvent ev) {
switch (ev.getAction()) {
case MotionEvent.ACTION_DOWN: {
float circ1Val = centreX + centreY;
float circ2Val = centreA + centreB;
float choice1 = circ1Val - (ev.getX() + ev.getY());
float choice2 = circ2Val - (ev.getX() + ev.getY());
float circleToBeMoved = choice1 < choice2 ? ;
. I'm not sure the best way to calculate the distance between each of the circles and the touch event. is this on the correct lines? or is there a better way? thanks
There is the following approach:
On ACTION_DOWN
you determine which circle lies next to the point touched. Therefore you calculate the distance from (centreX,centreY)
to (ev.getX(),ev.getY())
and from (centreA,centreB)
to (ev.getX(),ev.getY())
. If the first is smaller than the second you'll move the first circle otherwise the second circle (save this choice in a field circleToBeMoved
). Maybe you want to reject any movement if both distances are beyond a threshold (e.g. radius of the circles).
Second, on ACTION_MOVE
only move the circle contained in circleToBeMoved
(if any).
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