Regular expression capturing entire match consisting of repeated groups

I've looked thrould the forums but could not find exactly how exactly to solve my problem.

Let's say I have a string like the following:

UDK .636.32/38.082.4454.2(575.开发者_如何转开发3)

and I would like to match the expression with a regex, capturing the actual number (in this case the '.636.32/38.082.4454.2(575.3)').

There could be some garbage characters between the 'UDK' and the actual number, and characters like '.', '/' or '-' are valid parts of the number. Essentially the number is a sequence of digits separated by some allowed characters.

What I've came up with is the following regex:

'UDK.*(\d{1,3}[\.\,\(\)\[\]\=\'\:\"\+/\-]{0,3})+'

but it does not group the '.636.32/38.082.4454.2(575.3)'! It leaves me with nothing more than a last digit of the last group (3 in this case).

Any help would be greatly appreciated.

First, you need a non-greedy .*?. Second, you don't need to escape some chars in [ ]. Third, you might just consider it as a sequence of digits AND some allowed characters? Why there is a \d{1,3} but a 4454?

>>> re.match(r'UDK.*?([\d.,()\[\]=\':"+/-]+)', s).group(1)
'.636.32/38.082.4454.2(575.3)'

Not so much a direct answer to your problem, but a general regexp tip: use Kodos (http://kodos.sourceforge.net/). It is simply awesome for composing/testing out regexps. You can enter some sample text, and "try out" regular expressions against it, seeing what matches, groups, etc. It even generates Python code when you're done. Good stuff.

Edit: using Kodos I came up with:

UDK.*?(?P<number>[\d/.)(]+)

as a regexp which matches the given example. Code that Kodos produces is:

import re

rawstr = r"""UDK.*?(?P<number>[\d/.)(]+)"""
matchstr = """UDK .636.32/38.082.4454.2(575.3)"""

# method 1: using a compile object
compile_obj = re.compile(rawstr)
match_obj = compile_obj.search(matchstr)

# Retrieve group(s) by name
number = match_obj.group('number')