How can I extract email addresses from between '<' and '>'?

I've got a list of emails and names from Outlook, semicolon delimited, like this:

fname lname <email>; fname2 lname2 <email2>; ... ; fnameN lnameN <emailN>

And I'd like to extract the emails and semicolon delimit them like this:

email1; email2;开发者_运维问答 ... ; emailN

How can I do this in Python?

Using regex:

import re
# matches everything which is between < and > (excluding them)
ptrn = re.compile("<([^>]+)>")
# findall returns ['email','email2']. Join concats them.
print '; '.join(ptrn.findall("fname lname <email>; fname2 lname2 <email2>;"))
# email; email2

Using list comprehension:

em = "fname lname <email>; fname2 lname2 <email2>; fnameN lnameN <emailN>"
email_list = [entry.split()[-1][1:-1] for entry in em.split(';')]

# email_list:
# ['email', 'email2', 'emailN']

Breakdown:

for entry in em.split(';')

First it splits up the original string by the semi-colon.

entry.split()

Next it takes each entry, splits it again, this time by space.

entry.split()[-1]

Next it selects the last entry from the split, which is your email.

entry.split()[-1][1:-1]

This takes your email, which is in the form of "<email@addr.com>" and selects the string contained within the angle brackets ([1:-1] corresponds to select from the second character to second-to-last).

variations on a given theme:

s = 'fname lname <email>; fname2 lname2 <email2>; ... ; fnameN lnameN <emailN>'

print [ s[i+1 : i+s[i:].find('>')] for i,c in enumerate(s) if c == '<' ]

# OR

gen = ( i for i,c in enumerate(s) if c in '<>' )
print [ s[a+1:gen.next()] for a in gen]