Bash / apt - check package version before installation
The command "dpkg" has the option "-E" or "--skip-same-version" in order not to install a package if its same version is already installed.
From what I know "apt-get" does not have anything similar.
So I came up with this:
Installed=`sudo apt-开发者_开发技巧cache policy openjdk-6-jre | sed -n '2p' | cut -c 14-` #6b20-1.9.9-0ubuntu1~10.04.2
Candidate=`sudo apt-cache policy openjdk-6-jre | sed -n '3p' | cut -c 14-` #6b20-1.9.9-0ubuntu1~10.04.2
if [ "$Installed" -ne "$Candidate" ]; then
apt-get -fy install openjdk-6-jre
elif [ "$Installed" -eq "$Candidate" ]; then
echo 'Candidate version already installed.'
fi
My question: is there any other easier way of doing this? I am trying to use this information inside a bash script so that everything happens automatically...
Thanks.
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