Convert from hex character to Unicode character in python

The hex string '\xd3' can also be represe开发者_如何学Pythonnted as: Ó.

The easiest way I've found to get the character representation of the hex string to the console is:

print unichr(ord('\xd3'))

Or in English, convert the hex string to a number, then convert that number to a unicode code point, then finally output that to the screen. This seems like an extra step. Is there an easier way?

print u'\xd3'

Is all you have to do. You just need to somehow tell Python it's a unicode literal; the leading u does that. It will even work for multiple characters.

If you aren't talking about a literal, but a variable:

codepoints = '\xd3\xd3'
print codepoints.decode("latin-1")

Edit: Specifying a specific encoding when printing will not work if it's incompatible with your terminal encoding, so just let print do encode(sys.stdout.encoding) automatically. Thanks @ThomasK.

if data is something like this "\xe0\xa4\xb9\xe0\xa5\x88\xe0\xa4\xb2\xe0\xa5\x8b \xe0\xa4\x95\xe0\xa4\xb2"

sys.stdout.buffer.write(data) 

would print

हैलो कल

Not long ago, I had a very similar problem. I had to decode files that contained unicode hex (e.g., _x0023_) instead of special characters (e.g., #). The solution is described in the following code:

Script

from collections import OrderedDict
import re


def decode_hex_unicode_to_latin1(string: str) -> str:
    hex_unicodes = list(OrderedDict.fromkeys(re.findall(r'_x[?:\da-zA-Z]{4}_', string)))

    for code in hex_unicodes:
        char = bytes.fromhex(code[2:-1]).decode("latin1")[-1]
        string = string.replace(code, char)

    return string


def main() -> None:
    string = "|_x0020_C_x00f3_digo_x0020_|"
    decoded_string = decode_hex_unicode_to_latin1(string)
    print(string, "-->", decoded_string)

    return


if __name__ == '__main__':
    main()

Output

|_x0020_C_x00f3_digo_x0020_| --> | Código |