joining string to next string in list
I have a list with a large number of words in it: sentence = ['a','list','with','a','lot','of','strings','in','it']
I want to be be able to go through the list and combine pairs of words according to some conditions I have. e.g.
['a','list','with','a','lot','of','strings','in','it'] becomes ['a list','with','a lot','of','strings','in','it']
I have tried something like:
for w in range(len(sentence)):
if sentence[w] == 'a':
sentence[w:w+2]=[' '.joi开发者_如何学Cn(sentence[w:w+2])]
but it doesn't work because joining the strings, decreases the size of the list and causes an index out of range. Is there a way to do this with iterators and .next() or something?
You can use an iterator.
>>> it = iter(['a','list','with','a','lot','of','strings','in','it'])
>>> [i if i != 'a' else i+' '+next(it) for i in it]
['a list', 'with', 'a lot', 'of', 'strings', 'in', 'it']
This works in-place:
sentence = ['a','list','with','a','lot','of','strings','in','it']
idx=0
seen=False
for word in sentence:
if word=='a':
seen=True
continue
sentence[idx]='a '+word if seen else word
seen=False
idx+=1
sentence=sentence[:idx]
print(sentence)
yields
['a list', 'with', 'a lot', 'of', 'strings', 'in', 'it']
Somthing like this?
#!/usr/bin/env python
def joiner(s, token):
i = 0
while i < len(s):
if s[i] == token:
yield s[i] + ' ' + s[i+1]
i=i+2
else:
yield s[i]
i=i+1
sentence = ['a','list','with','a','lot','of','strings','in','it']
for i in joiner(sentence, 'a'):
print i
outputs:
a list
with
a lot
of
strings
in
it
You can use while
cycle and increase index w
manually.
A naive approach:
#!/usr/bin/env python
words = ['a','list','with','a','lot','of','strings','in','it']
condensed, skip = [], False
for i, word in enumerate(words):
if skip:
skip = False
continue
if word == 'a':
condensed.append(word + " " + words[i + 1])
skip = True
else:
condensed.append(word)
print condensed
# => ['a list', 'with', 'a lot', 'of', 'strings', 'in', 'it']
def grouped(sentence):
have_a = False
for word in sentence:
if have_a:
yield 'a ' + word
have_a = False
elif word == 'a': have_a = True
else: yield word
sentence = list(grouped(sentence))
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