Deliver rows to JavaScript using JSON
I'm trying to get the rows of my mysql table into Arrays, but I haven't found out how to do it correctly up till now. I would appreciate it if someone could give me a hint. It's probably very, very wrong the way I'm doing it, but I haven't found much information regarding JSON and my problem up till now.
function updateMap(){
var latlngArray = new Array();
var titleArray = new Array();
var ogvArray = new Array();
var mp4Array = new Array();
var webmArray = new Array();
$.getJSON('getPOI.php', function(data){
for(var i=0; data.length; i++){
latlngArray[i] = data[i][0];
alert(latlngArray[i]);
titleArray[i] = data[i][1];
ogvArray[i] = data[i][2];
mp4Array[i] = data[i][3];
webmArray[i] = data[i][4];
}
});
}
The phpfile:
$con = mysql_connect($server,$benutzername,$passwort) or
die ("Keine Verbindung moeglich");
mysql_select_db($datenbank, $con) or
die ("Die Datenbank existiert nicht");
$res = mysql_query("select * from POI");
echo json_encode($res);
mysql_close($con);
UPDATE: It still doesn't work properly. The alert function only displays "0: [object Object], 1: [object Object], ..." I guess I didnt access the data properly:
jsontest.html:
<html>
<head>
<script src="jquery-1.6.1.js"></script>
<script type="text/javascript">
function updateMap(){
$.getJSON('getPOI.php', function(data) {
$.each(data, function(key, value){
alert(key + ': ' + value);
});
}
);
}
</script>
</head>
<body onload="updateMap()">
</body>
</html>
getPOI.php:
<?php
$server = "localhost";
$benutzername = "user";
$passwort = "pw";
$datenbank = "d0116c39";
$con = mysql_connect($server,$benutzername,$passwort) or
die ("Keine Verbindung moeglich");
mysql_select_db($datenbank, $con) or
die ("Die Datenbank existiert nicht");
$allResults = array();
$res = mysql_query("select * from POI");
while ($row = mysql_fetch_assoc($res)) {
$allResults[] = $row;
}
echo json_encode($allResults);
?>
Finally got it:
<html>
<head>
<script src="jquery-1.6.1.js"></script>
<script type="text/javascript">
function updateMap(){
$.getJSON('getPOI.php', fun开发者_如何学运维ction(data) {
$.each(data, function(i, item){
alert(data[i]['Adresse']);
alert(data[i]['Titel']);
});
}
);
}
</script>
</head>
<body onload="updateMap()">
</body>
</html>
Calling this :
$res = mysql_query("select * from POI");
will execute the query, but not get you the data : you must fetch it.
This can be done with functions such as mysql_fetch_assoc() (which has to be called once per row the query has selected -- that's done in a loop, typically)
Each time you fetch a row, add it to an array.
And, when you're done fetching the rows and building up that array, json_encode() it, and echo the resulting string to the client.
You'll end up with a portion of code that could look a bit like this :
$allResults = array();
// Execute the query
$res = mysql_query("select * from POI");
// As long as you get rows, fetch them
while ($row = mysql_fetch_assoc($result)) {
// And add them to the resulting array
$allResults[] = $row;
}
// Which, in the end, can be JSON-encoded
echo json_encode($allResults);
加载中,请稍侯......
精彩评论