Get pixel color from canvas, on mousemove
Is it possible to get the RGB value pixel under the mouse? Is there a complete example of this? Here's what I have so far:
function draw() {
var ctx = document.getElementById('canvas').getContext('2d');
var img = new Image();
img.src = 'Your URL';
img.onload = function(){
ctx.dr开发者_开发知识库awImage(img,0,0);
};
canvas.onmousemove = function(e) {
var mouseX, mouseY;
if(e.offsetX) {
mouseX = e.offsetX;
mouseY = e.offsetY;
}
else if(e.layerX) {
mouseX = e.layerX;
mouseY = e.layerY;
}
var c = ctx.getImageData(mouseX, mouseY, 1, 1).data;
$('#ttip').css({'left':mouseX+20, 'top':mouseY+20}).html(c[0]+'-'+c[1]+'-'+c[2]);
};
}
Here's a complete, self-contained example. First, use the following HTML:
<canvas id="example" width="200" height="60"></canvas>
<div id="status"></div>
Then put some squares on the canvas with random background colors:
var example = document.getElementById('example');
var context = example.getContext('2d');
context.fillStyle = randomColor();
context.fillRect(0, 0, 50, 50);
context.fillStyle = randomColor();
context.fillRect(55, 0, 50, 50);
context.fillStyle = randomColor();
context.fillRect(110, 0, 50, 50);
And print each color on mouseover:
$('#example').mousemove(function(e) {
var pos = findPos(this);
var x = e.pageX - pos.x;
var y = e.pageY - pos.y;
var coord = "x=" + x + ", y=" + y;
var c = this.getContext('2d');
var p = c.getImageData(x, y, 1, 1).data;
var hex = "#" + ("000000" + rgbToHex(p[0], p[1], p[2])).slice(-6);
$('#status').html(coord + "<br>" + hex);
});
The code above assumes the presence of jQuery and the following utility functions:
function findPos(obj) {
var curleft = 0, curtop = 0;
if (obj.offsetParent) {
do {
curleft += obj.offsetLeft;
curtop += obj.offsetTop;
} while (obj = obj.offsetParent);
return { x: curleft, y: curtop };
}
return undefined;
}
function rgbToHex(r, g, b) {
if (r > 255 || g > 255 || b > 255)
throw "Invalid color component";
return ((r << 16) | (g << 8) | b).toString(16);
}
function randomInt(max) {
return Math.floor(Math.random() * max);
}
function randomColor() {
return `rgb(${randomInt(256)}, ${randomInt(256)}, ${randomInt(256)})`
}
See it in action here:
- https://bl.ocks.org/wayneburkett/ca41a5245a9f48766b7bc881448f9203
// set up some sample squares with random colors
var example = document.getElementById('example');
var context = example.getContext('2d');
context.fillStyle = randomColor();
context.fillRect(0, 0, 50, 50);
context.fillStyle = randomColor();
context.fillRect(55, 0, 50, 50);
context.fillStyle = randomColor();
context.fillRect(110, 0, 50, 50);
$('#example').mousemove(function(e) {
var pos = findPos(this);
var x = e.pageX - pos.x;
var y = e.pageY - pos.y;
var coord = "x=" + x + ", y=" + y;
var c = this.getContext('2d');
var p = c.getImageData(x, y, 1, 1).data;
var hex = "#" + ("000000" + rgbToHex(p[0], p[1], p[2])).slice(-6);
$('#status').html(coord + "<br>" + hex);
});
function findPos(obj) {
var curleft = 0, curtop = 0;
if (obj.offsetParent) {
do {
curleft += obj.offsetLeft;
curtop += obj.offsetTop;
} while (obj = obj.offsetParent);
return { x: curleft, y: curtop };
}
return undefined;
}
function rgbToHex(r, g, b) {
if (r > 255 || g > 255 || b > 255)
throw "Invalid color component";
return ((r << 16) | (g << 8) | b).toString(16);
}
function randomInt(max) {
return Math.floor(Math.random() * max);
}
function randomColor() {
return `rgb(${randomInt(256)}, ${randomInt(256)}, ${randomInt(256)})`
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<canvas id="example" width="200" height="60"></canvas>
<div id="status"></div>
I know this is an old question, but here's an alternative. I'd store that image data in an array, then, on mouse move event over the canvas:
var index = (Math.floor(y) * canvasWidth + Math.floor(x)) * 4
var r = data[index]
var g = data[index + 1]
var b = data[index + 2]
var a = data[index + 3]
A lot easier than getting the imageData everytime.
If you need to get the average color of a rectangular area, rather than the color of a single pixel, please take a look at this other question:
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