ANTLR: Syntax Errors are ignored when running parser programmatically
I am currently creating a more or less simple expression evaluator using ANTLR.
My grammar is straightforward (at least i hope so) and looks like this:
grammar SXLGrammar;
options {
language = Java;
output = AST;
}
tokens {
OR = 'OR';
AND = 'AND';
NOT = 'NOT';
GT = '>'; //greater then
GE = '>='; //greater then or equal
LT = '<'; //lower then
LE = '<='; //lower then or equal
EQ = '=';
NEQ = '!='; //Not equal
PLUS = '+';
MINUS = '-';
MULTIPLY = '*';
DIVISION = '/';
CALL;
}
@header {
package somepackage;
}
@members {
}
@lexer::header {
package rise.spics.sxl;
}
rule
: ('='|':')! expression
;
expression
: booleanOrExpression
;
booleanOrExpression
:
booleanAndExpression ('OR'^ booleanAndExpression)*
;
booleanAndExpression
:
booleanNotExpression ('AND'^ booleanNotExpression)*
;
booleanNotExpression
:
('NOT'^)? booleanAtom
;
booleanAtom
:
| compareExpression
;
compareExpression
:
commonExpression (('<' | '>' | '=' | '<=' | '>=' | '!=' )^ commonExpression)?
;
commonExpression
:
multExpr
(
(
'+'^
| '-'^
)
multExpr
)*
| DATE
;
multExpr
:
atom (('*'|'/')^ atom)*
| '-'^ atom
;
atom
:
INTEGER
| DECIMAL
| BOOLEAN
| ID
| '(' expression ')' -> expression
| functionCall
;
functionCall
:
ID '(' arguments ')' -> ^(CALL ID arguments?)
;
arguments
:
(expression) (','! expression)*
| WS
;
BOOLEAN
:
'true'
| 'false'
;
ID
:
(
'a'..'z'
| 'A'..'Z'
)+
;
INTEGER
:
('0'..'9')+
;
DECIMAL
:
('0'..'9')+ ('.' ('0'..'9')*)?
;
DATE
:
'!' '0'..'9' '0'..'9' '0'..'9' '0'..'9' '-' '0'..'9' '0'..'9' '-' '0'..'9' '0'..'9' 开发者_如何学Go(' ' '0'..'9' '0'..'9' ':''0'..'9' '0'..'9' (':''0'..'9' '0'..'9')?)?
;
WS
: (' '|'\t' | '\n' | '\r' | '\f')+ { $channel = HIDDEN; };
Now if i try to parse an invalid Expression like "= true NOT true", the graphical test-tool of the eclipse plugin throws an NoViableAltException: line 1:6 no viable alternative at input 'NOT', which is correct and supposed.
Now if i try to parse the expression in a Java Program, nothing happens. The Program
String expression = "=true NOT false";
CharStream input = new ANTLRStringStream(expression);
SXLGrammarLexer lexer = new SXLGrammarLexer(input);
TokenStream tokenStream = new CommonTokenStream(lexer);
SXLGrammarParser parser = new SXLGrammarParser(tokenStream);
CommonTree tree = (CommonTree) parser.rule().getTree();
System.out.println(tree.toStringTree());
System.out.println(parser.getNumberOfSyntaxErrors());
would output:
true
0
that means, the AST created by the parser exists of one node and ignores the rest. I'd like to handle syntax errors in my application, but its not possible if the generated parser doesn't find any error.
I also tried to alter the parser by overwriting the displayRecognitionError() method with something like this:
public void displayRecognitionError(String[] tokenNames,
RecognitionException e) {
String msg = getErrorMessage(e, tokenNames);
throw new RuntimeException("Error at position "+e.index+" " + msg);
}
but displayRecognitionError gets never called.
If i try something like "=1+", a error gets displayed. I guess theres something wrong with my grammar, but why does the eclipse plugin throw that error while the generated parser does not?
If you want rule
to consume the entire token-stream, you have to specify where you expect the end of your input. Like this:
rule
: ('='|':')! expression EOF
;
Without the EOF your parser reads the true
as boolean an ignores the rest.
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