string.search | number of hits
I'm searching for a number in a string, using the .search string method:
var myString = "20 fur bar 50";
alert(myString.search(/\d/);
This 开发者_运维问答returns the position of the first number: 0. How can I get the position of the second number? Is there a way to find out how many hits there are?
Use match
instead and the g
(global) flag.
jsFiddle.
If you don't want to match the digits individually, change it to \d+
.
jsFiddle.
How can I get the position of the second number?
myString.indexOf(myString.match(/\d/g)[1])
Is there a way to find out how many hits there are?
myString.match(/\d/g).length
Of course, I have hardcoded index 1 above, you have to do proper checks.
If you use exec
:
var myString = "20 fur bar 50";
var numberPositions = [];
var numberRe = /\d+/g;
for (var match; (match = numberRe.exec(myString));) {
numberPositions.push(
[numberRe.lastIndex - match[0].length, numberRe.lastIndex]);
}
then numberPositions
is an array of start (inclusive), end (exclusive) pairs:
[[0,2],[11,13]]
[0,2] is the range of characters (end-exclusive) for 20
and [11,13] is the corresponding range for 50
.
The regexp used there is /\d+/
instead of /\d/
so that instead of getting a separate range for 2
and 0
you get one range for the whole integer.
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