How do you format with Boost.Date_Time without leading zeros?
How can you format a boost::posix_time::ptime object without padding the numbers with zeros?
For example, I want to display 6/7/2011 6:30:25 PM
and not 06/07/2011 06:30:25 PM
.
In .NET, the format string wou开发者_如何学Cld be something like "m/d/yyyy h:mm:ss tt".
Here is some code to do it the wrong way, just to get an idea:
boost::gregorian::date baseDate(1970, 1, 1);
boost::posix_time::ptime shiftDate(baseDate);
boost::posix_time::time_facet *facet = new time_facet("%m/%d/%Y");
cout.imbue(locale(cout.getloc(), facet));
cout << shiftDate;
delete facet;
Output: 01/01/1970
To my knowledge this capability is not built into Boost.DateTime, but it's pretty trivial to write your own formatting functions, e.g.:
template<typename CharT, typename TraitsT>
std::basic_ostream<CharT, TraitsT>& print_date(
std::basic_ostream<CharT, TraitsT>& os,
boost::posix_time::ptime const& pt)
{
boost::gregorian::date const& d = pt.date();
return os
<< d.month().as_number() << '/'
<< d.day().as_number() << '/'
<< d.year();
}
template<typename CharT, typename TraitsT>
std::basic_ostream<CharT, TraitsT>& print_date_time(
std::basic_ostream<CharT, TraitsT>& os,
boost::posix_time::ptime const& pt)
{
boost::gregorian::date const& d = pt.date();
boost::posix_time::time_duration const& t = pt.time_of_day();
CharT const orig_fill(os.fill('0'));
os
<< d.month().as_number() << '/'
<< d.day().as_number() << '/'
<< d.year() << ' '
<< (t.hours() && t.hours() != 12 ? t.hours() % 12 : 12) << ':'
<< std::setw(2) << t.minutes() << ':'
<< std::setw(2) << t.seconds() << ' '
<< (t.hours() / 12 ? 'P' : 'A') << 'M';
os.fill(orig_fill);
return os;
}
I wholly agree with the other response: there does not seem to be a formatter specifier that gives the date with a single digit day-of-the-month.
In general, there is a way to use formatter strings (nearly identical to the common strftime
formats). These format specifiers look like, for example: "%b %d, %Y"
.
tgamblin provided a nice explanation here.
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