python, cleaning a list

Trying to clean up a python list, I am able to remove exact string matches. How do I remove partial matches?

exclude = ['\n','Hits','Sites','blah','blah2','partial string','maybe here']
newlist = []
for item in array:
 开发者_运维技巧   if item not in exclude:
        newlist.append(item)

Problem here is "item not in exclude"... which does exact matching.

Should I use the following method:

s = "This be a string"
if s.find("is") == -1:
    print "No 'is' here!"
else:
    print "Found 'is' in the string."

In a way i answered my own question :) I guess is there an operand alternative to 'in' ?

Thanks

Try the following generator instead:

def remove_similar(array, exclude):
    for item in array:
        for fault in exclude:
            if fault in item:
                break
        else:
            yield item

Is this what you are searching for?

blacklist = ['a', 'b', 'c']
cleaned = []
for item in ['foo', 'bar', 'baz']:
    clean = True
    for exclude in blacklist:
        if item.find(exclude) != -1:
            clean = False
            break
    if clean:
        cleaned.append(item)
print cleaned # --> ['foo']

I'm not sure what you're asking here. Do you want to filter out all elements in array that are substrings of an element of exclude? If so, you could replace your line

if item not in exclude:

with something like

if not any(item in e for e in exclude):

exclude = ['\n','Hits','Sites','blah','blah2','partial string','maybe here']
newlist = []
for item in array:
        ok = True
        for excItem in exclude:
                if excItem in item: 
                    ok = False
                    break
        if ok: newlist.append(item)

how about:

all( s.find(e) == -1 for e in exclude )

which will return True if none of the exclude strings are found as substrings in s.

if by partial you mean that s is a substring of e, then:

not any( e.find(s) != -1 for e in exclude )

would return True if s is not found as a substring in any of the strings in exclude