How do I get the picture size with PIL?
How do I 开发者_JAVA技巧get a size of a pictures sides with PIL or any other Python library?
from PIL import Image
im = Image.open('whatever.png')
width, height = im.size
According to the documentation.
You can use Pillow (Website, Documentation, GitHub, PyPI). Pillow has the same interface as PIL, but works with Python 3.
Installation
$ pip install Pillow
If you don't have administrator rights (sudo on Debian), you can use
$ pip install --user Pillow
Other notes regarding the installation are here.
Code
from PIL import Image
with Image.open(filepath) as img:
width, height = img.size
Speed
This needed 3.21 seconds for 30336 images (JPGs from 31x21 to 424x428, training data from National Data Science Bowl on Kaggle)
This is probably the most important reason to use Pillow instead of something self-written. And you should use Pillow instead of PIL (python-imaging), because it works with Python 3.
Alternative #1: Numpy (deprecated)
I keep scipy.ndimage.imread
as the information is still out there, but keep in mind:
imread is deprecated! imread is deprecated in SciPy 1.0.0, and [was] removed in 1.2.0.
import scipy.ndimage
height, width, channels = scipy.ndimage.imread(filepath).shape
Alternative #2: Pygame
import pygame
img = pygame.image.load(filepath)
width = img.get_width()
height = img.get_height()
Since scipy
's imread
is deprecated, use imageio.imread
.
- Install -
pip install imageio
- Use
height, width, channels = imageio.imread(filepath).shape
This is a complete example loading image from URL, creating with PIL, printing the size and resizing...
import requests
h = { 'User-Agent': 'Neo'}
r = requests.get("https://images.freeimages.com/images/large-previews/85c/football-1442407.jpg", headers=h)
from PIL import Image
from io import BytesIO
# create image from binary content
i = Image.open(BytesIO(r.content))
width, height = i.size
print(width, height)
i = i.resize((100,100))
display(i)
Note that PIL will not apply the EXIF rotation information (at least up to v7.1.1; used in many jpgs). A quick fix to accomodate this:
def get_image_dims(file_path):
from PIL import Image as pilim
im = pilim.open(file_path)
# returns (w,h) after rotation-correction
return im.size if im._getexif().get(274,0) < 5 else im.size[::-1]
Here's how you get the image size from the given URL in Python 3:
from PIL import Image
import urllib.request
from io import BytesIO
file = BytesIO(urllib.request.urlopen('http://getwallpapers.com/wallpaper/full/b/8/d/32803.jpg').read())
im = Image.open(file)
width, height = im.size
Followings gives dimensions as well as channels:
import numpy as np
from PIL import Image
with Image.open(filepath) as img:
shape = np.array(img).shape
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