How can I splice a string?
I know I can slice a string in Python by using array notation: str[1:6]
, but how do I splice it? i.e., replace 开发者_开发技巧str[1:6]
with another string, possibly of a different length?
Strings are immutable in Python. The best you can do is construct a new string:
t = s[:1] + "whatever" + s[6:]
You can't do this since strings in Python are immutable.
Try next:
new_s = ''.join((s[:1], new, s[6:]))
Nevermind. Thought there might be a built in function. Wrote this instead:
def splice(a,b,c,d=None):
if isinstance(b,(list,tuple)):
return a[:b[0]]+c+a[b[1]:]
return a[:b]+d+a[c:]
>>> splice('hello world',0,5,'pizza')
'pizza world'
>>> splice('hello world',(0,5),'pizza')
'pizza world'
Python strings are immutable, you need to manually:
new = str[:1] + new + str[6:]
What about such try?
>>> str = 'This is something...'
>>> s = 'Theese are'
>>> print str
This is something...
>>> str = str.replace(str[0:7], s)
>>> print str
Theese are something...
For a more "JavaScript compliant" string splice:
def splice(target, start, delete_count='', insert=''):
"""
>>> splice('hello pizza world', 6, 5, 'pasta')
('hello pasta world', 'pizza')
>>> s = 'hello pizza world'
>>> s, food = splice(s, (6, 5), 'pasta')
>>> s, food
('hello pasta world', 'pizza')
"""
if isinstance(start, (list, tuple)):
insert = delete_count
start, delete_count = start
delete_count += start
return target[:start] + insert + target[delete_count:], target[start:delete_count]
Note that because string arguments are immutable in Python, it is necessary to return two parameters: the modified string, and the removed text.
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