I don't think this can be done with cleartool find to get all LATEST for a file

Basically I would like to do:

cleartool find . -version 'version(.../LATEST)' -print 
| egrep '\\.[CH]@@' 
| xargs -I {} grep 'TEXT' {} \; 

But version requires a branch name if using .../ and I want to get all branches for the files.

I know you can cheat and get all branches by using -branch '\!attype(dummyname)' but the branch name is only the first step.

I would like to be able to grep all of the L开发者_JS百科ATEST versions on all of the branches and the main for -name '*.[CH]' files in the VOB.

I have made a script to use the above dummyname to get all branches, grep '\\.[CH]@@', append LATEST to it and grep that file name for what I am looking for but it is very slow to do it that way.

I confirm this will be slow, and that the -branch '\!attype(dummyname)' seems to be the only way to list all branches, according to IBM cleartool find examples.

I would try first to find all *.ch file versions, and sort that out per branches to isolates the latest. That might be quicker.