Losing elements in python code while creating a dictionary from a list?
I have some headache w开发者_运维问答ith this python code.
print "length:", len(pub) # length: 420
pub_dict = dict((p.key, p) for p in pub)
print "dict:", len(pub_dict) # length: 163
If I understand this right, I get a dictionary containing the attribute p.key
as key and the object p
as its value for each element of pub
. Are there some side effect I don't see? Because len(pub_dict)
should be the same as len(pub)
and it is certainly not here, or am I mistaken?
Since you may have several p with the same key then you may use list as value for you key within new dicitionary:
pub_dict = {}
for p in pub:
if not p.key in pub_dict:
pub_dict[p.key] = []
pub_dict[p.key].append(p)
Or if it is neccessary for you to uniquely identify each record you may use any combined key like key + any other p propery value
pub_dict = {}
for i,p in enumerate(pub):
pub_dict[p.key] = p
print i+1,len(pub_dict)
would have give you light on the problem
精彩评论