When we call getMonth() and getDate() on date object, we will get the single d开发者_如何转开发igit number. For example :

For january, it displays 1, but I need to display it as 01. How to do that?

("0" + this.getDate()).slice(-2)

for the date, and similar:

("0" + (this.getMonth() + 1)).slice(-2)

for the month.

If you want a format like "YYYY-MM-DDTHH:mm:ss", then this might be quicker:

var date = new Date().toISOString().substr(0, 19);
// toISOString() will give you YYYY-MM-DDTHH:mm:ss.sssZ

Or the commonly used MySQL datetime format "YYYY-MM-DD HH:mm:ss":

var date2 = new Date().toISOString().substr(0, 19).replace('T', ' ');

Why not use padStart ?

padStart(targetLength, padString) where

• targetLength is 2
• padString is 0

// Source: https://stackoverflow.com/a/50769505/2965993

var dt = new Date();

year  = dt.getFullYear();
month = (dt.getMonth() + 1).toString().padStart(2, "0");
day   = dt.getDate().toString().padStart(2, "0");

console.log(year + '/' + month + '/' + day);

This will always return 2 digit numbers even if the month or day is less than 10.

Notes:

• This will only work with Internet Explorer if the js code is transpiled using babel.
• getFullYear() returns the 4 digit year and doesn't require padStart.
• getMonth() returns the month from 0 to 11.
  • 1 is added to the month before padding to keep it 1 to 12.
• getDate() returns the day from 1 to 31.
  • The 7th day will return 07 and so we do not need to add 1 before padding the string.

Example for month:

function getMonth(date) {
  var month = date.getMonth() + 1;
  return month < 10 ? '0' + month : '' + month; // ('' + month) for string result
}  

You can also extend Date object with such function:

Date.prototype.getMonthFormatted = function() {
  var month = this.getMonth() + 1;
  return month < 10 ? '0' + month : '' + month; // ('' + month) for string result
}

The best way to do this is to create your own simple formatter (as below):

getDate() returns the day of the month (from 1-31)
getMonth() returns the month (from 0-11) < zero-based, 0=January, 11=December
getFullYear() returns the year (four digits) < don't use getYear()

function formatDateToString(date){
   // 01, 02, 03, ... 29, 30, 31
   var dd = (date.getDate() < 10 ? '0' : '') + date.getDate();
   // 01, 02, 03, ... 10, 11, 12
   var MM = ((date.getMonth() + 1) < 10 ? '0' : '') + (date.getMonth() + 1);
   // 1970, 1971, ... 2015, 2016, ...
   var yyyy = date.getFullYear();

   // create the format you want
   return (dd + "-" + MM + "-" + yyyy);
}

I would do this:

var date = new Date(2000, 0, 9);
var str = new Intl.DateTimeFormat('en-US', {
  month: '2-digit',
  day: '2-digit',
  year: 'numeric'
}).format(date);

console.log(str); // prints "01/09/2000"

The following is used to convert db2 date format i.e YYYY-MM-DD using ternary operator

var currentDate = new Date();
var twoDigitMonth=((currentDate.getMonth()+1)>=10)? (currentDate.getMonth()+1) : '0' + (currentDate.getMonth()+1);  
var twoDigitDate=((currentDate.getDate())>=10)? (currentDate.getDate()) : '0' + (currentDate.getDate());
var createdDateTo = currentDate.getFullYear() + "-" + twoDigitMonth + "-" + twoDigitDate; 
alert(createdDateTo);

Just another example, almost one liner.

var date = new Date();
console.log( (date.getMonth() < 9 ? '0': '') + (date.getMonth()+1) );

function monthFormated(date) {
   //If date is not passed, get current date
   if(!date)
     date = new Date();

     month = date.getMonth();

    // if month 2 digits (9+1 = 10) don't add 0 in front 
    return month < 9 ? "0" + (month+1) : month+1;
}

If it might spare some time I was looking to get:

YYYYMMDD

for today, and got along with:

const dateDocumentID = new Date()
  .toISOString()
  .substr(0, 10)
  .replace(/-/g, '');

function monthFormated() {
  var date = new Date(),
      month = date.getMonth();
  return month+1 < 10 ? ("0" + month) : month;
}

This was my solution:

function leadingZero(value) {
  if (value < 10) {
    return "0" + value.toString();
  }
  return value.toString();
}

var targetDate = new Date();
targetDate.setDate(targetDate.getDate());
var dd = targetDate.getDate();
var mm = targetDate.getMonth() + 1;
var yyyy = targetDate.getFullYear();
var dateCurrent = leadingZero(mm) + "/" + leadingZero(dd) + "/" + yyyy;

Using Moment.js it can be done like that:

moment(new Date(2017, 1, 1)).format('DD') // day
moment(new Date(2017, 1, 1)).format('MM') // month

const today = new Date().toISOString()
const fullDate = today.split('T')[0];
console.log(fullDate) //prints YYYY-MM-DD

Not an answer but here is how I get the date format I require in a variable

function setDateZero(date){
  return date < 10 ? '0' + date : date;
}

var curr_date = ev.date.getDate();
var curr_month = ev.date.getMonth() + 1;
var curr_year = ev.date.getFullYear();
var thisDate = curr_year+"-"+setDateZero(curr_month)+"-"+setDateZero(curr_date);

Hope this helps!

Ternary Operator Solution

A simple ternary operator can add a "0" before the number if the month or day is less than 10 (assuming you need this information for use in a string).

let month = (date.getMonth() < 10) ? "0" + date.getMonth().toString() : date.getMonth();
let day = (date.getDate() < 10) ? "0" + date.getDate().toString() : date.getDate();

The more modern approach perhaps, using "padStart"

const now = new Date();
const day = `${now.getDate()}`.padStart(2, '0');
const month = `${now.getMonth()}`.padStart(2, '0');
const year = now.getFullYear();

then you can build as a template string if you wish:

`${day}/${month}/${year}`

Tip from MDN :

function date_locale(thisDate, locale) {
  if (locale == undefined)
    locale = 'fr-FR';
  // set your default country above (yes, I'm french !)
  // then the default format is "dd/mm/YYY"

  if (thisDate == undefined) {
    var d = new Date();
  } else {
    var d = new Date(thisDate);
  }
  return d.toLocaleDateString(locale);
}

var thisDate = date_locale();
var dayN = thisDate.slice(0, 2);
var monthN = thisDate.slice(3, 5);
console.log(dayN);
console.log(monthN);

http://jsfiddle.net/v4qcf5x6/

new Date().getMonth() method returns the month as a number (0-11)

You can get easily correct month number with this function.

function monthFormatted() {
  var date = new Date(),
      month = date.getMonth();
  return month+1 < 10 ? ("0" + month) : month;
}

I would suggest you use a different library called Moment https://momentjs.com/

This way you are able to format the date directly without having to do extra work

const date = moment().format('YYYY-MM-DD')
// date: '2020-01-04'

Make sure you import moment as well to be able to use it.

yarn add moment 
# to add the dependency

import moment from 'moment' 
// import this at the top of the file you want to use it in

Hope this helps :D

How it easy?

new Date().toLocaleString("en-US", { day: "2-digit" })

Another options are available such:

• weekday
• year
• month

More info here. https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Date/toLocaleDateString#using_options

function GetDateAndTime(dt) {
  var arr = new Array(dt.getDate(), dt.getMonth(), dt.getFullYear(),dt.getHours(),dt.getMinutes(),dt.getSeconds());

  for(var i=0;i<arr.length;i++) {
    if(arr[i].toString().length == 1) arr[i] = "0" + arr[i];
  }

  return arr[0] + "." + arr[1] + "." + arr[2] + " " + arr[3] + ":" + arr[4] + ":" + arr[5]; 
}

And another version here https://jsfiddle.net/ivos/zcLxo8oy/1/, hope to be useful.

var dt = new Date(2016,5,1); // just for the test
var separator = '.';
var strDate = (dt.getFullYear() + separator + (dt.getMonth() + 1) + separator + dt.getDate());
// end of setup

strDate = strDate.replace(/(\b\d{1}\b)/g, "0$1")

The answers here were helpful, however I need more than that: not only month, date, month, hours & seconds, for a default name.

Interestingly, though prepend of "0" was needed for all above, " + 1" was needed only for month, not others.

As example:

("0" + (d.getMonth() + 1)).slice(-2)     // Note: +1 is needed
("0" + (d.getHours())).slice(-2)         // Note: +1 is not needed

My solution:

function addLeadingChars(string, nrOfChars, leadingChar) {
    string = string + '';
    return Array(Math.max(0, (nrOfChars || 2) - string.length + 1)).join(leadingChar || '0') + string;
}

Usage:

var
    date = new Date(),
    month = addLeadingChars(date.getMonth() + 1),
    day = addLeadingChars(date.getDate());

jsfiddle: http://jsfiddle.net/8xy4Q/1/

var net = require('net')

function zeroFill(i) {
  return (i < 10 ? '0' : '') + i
}

function now () {
  var d = new Date()
  return d.getFullYear() + '-'
    + zeroFill(d.getMonth() + 1) + '-'
    + zeroFill(d.getDate()) + ' '
    + zeroFill(d.getHours()) + ':'
    + zeroFill(d.getMinutes())
}

var server = net.createServer(function (socket) {
  socket.end(now() + '\n')
})

server.listen(Number(process.argv[2]))

if u want getDate() function to return the date as 01 instead of 1, here is the code for it.... Lets assume Today's date is 01-11-2018

var today = new Date();
today = today.getFullYear()+ "-" + (today.getMonth() + 1) + "-" + today.getDate();      
console.log(today);       //Output: 2018-11-1


today = today.getFullYear()+ "-" + (today.getMonth() + 1) + "-" + ((today.getDate() < 10 ? '0' : '') + today.getDate());
console.log(today);        //Output: 2018-11-01

I wanted to do something like this and this is what i did

p.s. i know there are right answer(s) on top, but just wanted to add something of my own here

const todayIs = async () =>{
    const now = new Date();
    var today = now.getFullYear()+'-';
    if(now.getMonth() < 10)
        today += '0'+now.getMonth()+'-';
    else
        today += now.getMonth()+'-';
    if(now.getDay() < 10)
        today += '0'+now.getDay();
    else
        today += now.getDay();
    return today;
}

If you'll check smaller than 10, you haven't to create a new function for that. Just assign a variable into brackets and return it with ternary operator.

(m = new Date().getMonth() + 1) < 10 ? `0${m}` : `${m}`

currentDate(){
        var today = new Date();
        var dateTime =  today.getFullYear()+'-'+
                        ((today.getMonth()+1)<10?("0"+(today.getMonth()+1)):(today.getMonth()+1))+'-'+
                        (today.getDate()<10?("0"+today.getDate()):today.getDate())+'T'+
                        (today.getHours()<10?("0"+today.getHours()):today.getHours())+ ":" +
                        (today.getMinutes()<10?("0"+today.getMinutes()):today.getMinutes())+ ":" +
                        (today.getSeconds()<10?("0"+today.getSeconds()):today.getSeconds());        
            return dateTime;
},