Regex for xxxx.xxx.xxx

I need to validate a Vat number.

xxxx.xxx.xxx --> 0123.456.789 is a valid number.

I found a regex

^(BE)[0-1]{1}[0-9]{9}$|^((BE)|(BE ))[0-开发者_StackOverflow中文版1]{1}(\d{3})([.]{1})(\d{3})([.]{1})(\d{3})

This validate the following entry: BE 0123.456.789.

But what i need is to validate only xxxx.xxx.xxx ( nothing else is valid , only this )

So 4 digits , a point , 3 digits , a point , 3 digits.

Also it needs to begin with 0 or 1 ( first x --> 0 or 1 )

Here you go:

^[01]\d{3}\.\d{3}\.\d{3}$

Breakdown:

^      - Start of string
[01]   - Followed by a 0 or 1
\d{3}  - Followed by three numerals
\.     - Followed by a .
\d{3}  - Followed by three numerals
\.     - Followed by a .
\d{3}  - Followed by three numerals
$      - Followed by end of string

This should work:

^[01]\d{3}\.\d{3}\.\d{3}$

This is the expression

^[0-1]\d{3}[.]\d{3}[.]\d{3}$

^     // start of the input
\d{#} // numbers repeated # times
[.]   // literal . (same as  \.  )
$     // end of the input

If the patter you need to match really is: 4 digits , a point , 3 digits , a point , 3 digits. and begin with 0 or 1

then try this:

^[01]\d{3}\.\d{3}\.\d{3}$

You want:

^[01]\d{3}\.\d{3}\.\d{3}$

As others have pointed out, one way is

^[01]\d{3}\.\d{3}\.\d{3}$

This is the correct regex if you want to allow any digits (incl. non-Arabic ones), as \d is the same as [:digit:], which matches any character marked as a digit in Unicode.

If you only want to allow Arabic digits (and it sounds like you do), you should use [0-9] instead of \d:

^[01][0-9]{3}\.[0-9]{3}\.[0-9]{3}$

If that is exactly what you want to validate, you only need this:

^[01]\d{3}\.\d{3}\.\d{3}$

This does exactly what you said in the question: 0 or 1, 3 digits, point, 3 digits, point, 3 digits. Be aware that your regex in your question is more different from what you want than just the BE, however, if you found it in reference to VAT numbers then it also might be more correct or accept more common forms of VAT numbers.