jQuery-UI Draggable: Print out the coordinate relative to a DIV container
This demo shows how send event when dragging the component around using jQuery. I have a component inside a DIV
, and when I drag that component I want to print out the coordinate of the component relative to the DIV
container, can any jQuery pro help me out here. Here is what I got so far.
<div id="container" style="width: 400px; height: 4000px; border: 1px solid black;" >
<div id="draggable" style="width: 150px; height: 150px; background-color开发者_Python百科: black; cursor: move;">
<div class="count"/>
</div>
</div>
<script>
jQuery(function(){
jQuery("#draggable").draggable({
containment: "#contain",
scroll: false,
drag: function(){
}
});
function updateCoordinate(newCoordinate){
jQuery(".count").text(newCoordinate);
}
});
</script>
In the callback event for drag, I need to figure out the pageX, pageY
as well as the offsetX, offsetY
to find out the relative position of the component when i drag. I am very new to jQuery. I know that I can obtain the both pageX, pageY
and offsetX, offsetY
like this
jQuery("#container").click(function(event){
var offset = jQuery(this).offset();
var pageX = event.pageX;
var pageY = event.pageY;
});
but I am not sure how to combine them together.
Like this?
http://jsfiddle.net/aasFx/36/
$(function() {
$("#draggable").draggable({
containment: "#contain",
scroll: false,
drag: function() {
var $this = $(this);
var thisPos = $this.position();
var parentPos = $this.parent().position();
var x = thisPos.left - parentPos.left;
var y = thisPos.top - parentPos.top;
$this.text(x + ", " + y);
}
});
});
What you might want to do is set the parent container CSS to 'position: relative', and the 'draggable item' to 'position: absolute'. Then, using things like $(this).position().left / top will be relative to the parent container.
See here: http://jsfiddle.net/bTULc/1/
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