What's wrong with this python script?

RAM=open('/root/arg2', 'r').read()
if RAM=="":
        try:
            if not sys.argv[2]=="":
                f = open("/root/arg2","a")
                f.write(sys.argv[2])
                f.close()   
    if float(RAM) > 4096:
        os.system("echo What the hell?")

What's wrong with the script above? The line after f.close() always gives error when compiling. Error from compiling开发者_运维百科:

riki137@riki137-K70IC:~/scripts$ python -m compileall *
Compiling thatscript.py ...
Sorry: IndentationError: ('unexpected unindent', ('thatscript.py', 20, 1, '\tif float(RAM) > 4096:\n'))

I have tried spaces, different commands, new blank lines. None of that solved it.

You need to have an except or finally block for your try.

If you don't want to do anything in the event of an exception just put pass in it.

    try:
        if not sys.argv[2]=="":
            f = open("/root/arg2","a")
            f.write(sys.argv[2])
            f.close()
    except:
        pass

Failing to have this block can cause the IndentationError you're experiencing:

  try:
    foo = 1
    bar = 2
  baz = 3

  File "<pyshell#13>", line 5
    baz = 3
          ^
IndentationError: unindent does not match any outer indentation level

You must follow the try block with a catch or finally block at the same tab level

Remove the try: statement, as it's not doing anything.

RAM=open('/root/arg2', 'r').read()
if RAM=="":
    if not sys.argv[2]=="":
        f = open("/root/arg2","a")
        f.write(sys.argv[2])
        f.close()   

Others have stated this too, but I'd be wary of just using an empty except: block, as this could lead you to believe things had been done that had infact failed.

Also, your next statement will fail, as if RAM=="" then float(RAM) will raise a ValueError. This might be an indentation problem with your question, but it should probably look something like:

if RAM=="":
    #Your sys.argv bit here
elif float(RAM) > 4096:
    os.system("echo What the hell?")