PHP not reading command line params

I created a small script I use for 'cleaning' sitemap file from certain links. I think I used it before with no problems, but am unable to use it now because of a strange bug - no 开发者_C百科command line params are read at all.

I'm probably looking at the wrong place, but I googled and all I get is the usage I'm implementing already.

Please check the following code snippet:

 if(count($argv) != 4) {
            echo "\n\nUSAGE: php cleanSitemap.php <input file> <output file> <bad str>\n"
                    ."This script parses <input file>, skipping all the sitemap XML elements containing <bad str>,\n"
                    ."writting only 'good' XML elements into sitemap.\n"
                    ."Sample: php cleanSitemap.php sitemap.xml sitemap_clean.xml protect-x\n"
                    ."\n";
            echo "You entered " . count($argv) . " parameters.\n";
            exit();
    }

What do you think, where is the problem???

EDIT: To simplify things, I created test.php with following content:

<?php
        echo count($argv) ."\n";
        print_r($argv);
        echo "\n";
?>

-bash-3.2$ /web/cgi-bin/php5 test.php 1 2 3 45

Content-type: text/html

0

Ok... While writing this, I think I may have come to something: this is php5 client used on Godaddy shared hosting. Maybe it's somehow set not to be used via command line? Or, if used, it's not accepting command line arguments.

Ohhhhhhhhhhh... Ok, I'm a total noob.

I have just found out that this problem was really related to the use of the incorrect php binary... Namely, the 'right' one could be found in /usr/local/php5/bin/php .

I'm really sorry for this mistake.