batch echo pipe symbol causing unexpected behaviour
I have a variable in my b开发者_如何学Goatch file and it contains the pipe symbol (this one: |) so when I echo the variable I get an error about a unrecognized internal/external command.
I need a way to either get it to echo it correctly or better yet remove everything after and including the | symbol as well as any extra spaces before it.
There are several special characters that generally must be escaped when used in Windows batch files. Here is a partial list: < > & | ^ %
The escape character is ^
. So to get a literal |
, you should do this:
echo ^|
When the special character is in a variable, it becomes a bit harder. But if you use special syntax, you can replace characters in a variable like this:
set X=A^|B
REM replace pipe character with underscore
set Y=%X:|=_%
echo %Y%
REM prints "A_B"
You must escape the | character before you print the var. The following prints a|b
@echo off
set x=a^|b
echo %x:|=^|%
The question did not specify the OS. For unix:
escape it
echo \|
or wrap in quotes
echo "|"
Old question, but there is one unmentioned solution, much easier to use:
Delayed Expansion
Using delayed expansion has the advantage, that any content can be used without modifications, there aren't any problematic characters at all.
set "test=A|B&C,D"E^<F^>G"
setlocal EnableDelayedExpansion
echo !test!
set test --- Works, but shows also: "test=..."
echo %test% --- This one fails
set X=%0^|callset.bat
set Y=%X:|=_%
echo %Y%
echo %X% _ %Y%
REM activate callset | more
REM and you should have infinite pipe. Break CTRL+C twice Ctrl Break REM prints "The process tried to write to a nonexistent pipe."
Henrik's answer works fine if you simply want to echo the contents of a variable to the screen, but if you want to pipe a value containing a pipe symbol into another program (as I did) you need to add more carets (^
):
Echo bare text containing a pipe (|
):
echo Hello ^| world
Set-and-echo variable containing a pipe (|
):
set txt=Hello ^| world
echo %txt:|=^|%
Echo bare text containing a pipe (|
) into another program:
echo Hello ^^^| world | hexdump
produces:
000000 48 65 6c 6c 6f 20 7c 20 - 77 6f 72 6c 64 20 0a Hello | world .
Set-and-echo variable containing a pipe (|
) into another program:
set txt=Hello ^| world
echo %txt:|=^^^|% | hexdump
produces:
000000 48 65 6c 6c 6f 20 7c 20 - 77 6f 72 6c 64 20 0a Hello | world .
(hexdump
is just a utility I have to dump stdin
in hex and ASCII).
The reason three carets (^^^
) are needed (as I think I understand it) is because CMD essentially parses the command-line twice: once to identify that it contains an un-escaped pipe (the | hexdump
bit); then each part gets processed a second time as it goes to execute them.
The first pass turns echo Hello ^^^| world
into echo ^| world
(read the middle bit as ^^
followed by ^|
: an escaped caret and an escaped pipe). When it is processed the second time – while executing the pipeline – the "surviving" caret protects the pipe symbol so that Hello | world
is fed into the next command.
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