Very simple c++ for statement but it wont cout?

My question is simple. I have a 'for' statement in a c++ program and when I compile ignores my cout.

I am using xcode, compiling with xcode and here is my code:

#include <iostream>
using namespace s开发者_Python百科td;

    int main () 
    {
      cout << this prints" << endl;
      for(int i=0; i>10; i++)
       {
         cout << "this doesn't" << endl;
       }
     return 0;
    }

What is the problem?

for(int i=0; i>10; i++)

You initialize i to 0 then only enter the body of the loop if i is greater than 10.

The loop loops as long as the condition i > 10 is true, not until the condition i > 10 is true. This is how all the loops in C++ work: for, while, and do/while.

Your loop condition is backwards. You want it to be i < 10.

You have got the condition for loop incorrect. This should work. Check below:

#include <iostream>
using namespace std;

int main () 
{
    cout << "this prints" << endl;
    for(int i=0; i<= 10; i++)   // ------> Check the change in condition here
    {
        cout << "this doesn't" << endl;
    }
    return 0;
}