php SimpleCassie Cassandra TimeUUID
I created a column family Users using following command:
create column family Users with comparator=TimeUUIDType and default_validation_class=UTF8Type;
Then I insert a column into Users. It shows as follows.
RowKey: jsmith
=>(column=66829930-515b-11e0-8443-0f82b246fa40, value=hello, timestamp=1300451382)
I want to access it using SimpleCassie. The command is:
$data = $cassie->keyspace('Keyspace1')->cf('Users')->key('jsmith')->column('66829930-515b-11e0-8443-0f82b246fa40')->value();
(I also tried: $data = $cassie->keyspace('Keyspace1')->cf('Users')->key('jsmith')->column($cassie->uuid('66829930-515b-11e0-8443-0f82b246f开发者_开发问答a40')->__toString())->value();
)
However, They do not work. It always return NULL. How can I get the column value (hello) I want?
Try:
$cassie->keyspace('Keyspace1')->cf('Users')->key('jsmith')->column($cassie->uuid('66829930-515b-11e0-8443-0f82b246fa40')->uuid)->value();)
Cassandra expects the binary representation of a UUID, not a hex/string representation.
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