Python: what is the fastest / most elegant way to see if every number in two arrays is the same?

ie, compare:

1,-1,1 

to

1.0,-1, 1

should be the same

print("the input and the output are " + ( (input == calc_out) ? "the sam开发者_StackOverflow社区e" : "not the same"))

but it give a lexical error =\

The docs indicate various ways you can compare sequences and other types:

(1, 2, 3)              < (1, 2, 4)
[1, 2, 3]              < [1, 2, 4]
'ABC' < 'C' < 'Pascal' < 'Python'
(1, 2, 3, 4)           < (1, 2, 4)
(1, 2)                 < (1, 2, -1)
(1, 2, 3)             == (1.0, 2.0, 3.0)
(1, 2, ('aa', 'ab'))   < (1, 2, ('abc', 'a'), 4)

So for your example:

C:\Users\jon>python
Python 2.6.5 (r265:79096, Mar 19 2010, 21:48:26) [MSC v.1500 32 bit (Intel)] on win32
Type "help", "copyright", "credits" or "license" for more information.
>>> [1,-1,1] == [1.0,-1,1]
True

==

found it... Python does Ternary weird:

print("the input and the output are " + ( "the same" if (input == calc_out)  else "not the same"))