Python Adventure Game -> Chose A or B in a while loop not working!
I'm trying to create a simple adventure game in Python. I've come to a point where I need to ask the user if they wish to choose option A or B and am using a while loop to try and do this:
AB = input("A or B?")
while AB != "A" or "a" or "B" or "b":
input("Choose either A or B")
if AB == "A" or "a":
print("A")
elif AB == "B"开发者_如何学Python or "b":
print("B")
The thing is, no matter what you input, the question "Choose either A or B" comes up. What am I doing wrong?
Your while
statement is evaluating on the conditionals or
, which is always true for the strings you provided.
while AB != "A" or "a" or "B" or "b":
means:
while (AB != "A") or "a" or "B" or "b":
Non-empty strings are always True, so writing or "B"
will always be true, and will always ask for input. Better to write:
while AB.lower() not in ('a','b'):
AB != "A" or "a" or "B" or "b"
should be
AB.upper() not in ('A','B')
AB != "A" or "a" or "B" or "b"
is interpreted as
(AB != "A") or ("a") or ("B") or ("b")
and since "a"
is always true
, the result of this check will always be true
.
It would be better to use:
AB = raw_input("A or B?").upper()
and then the not in
construct as others have suggested.
Use the raw_input()
function, instead, like this:
ab = raw_input('Choose either A or B > ')
while ab.lower() not in ('a', 'b'):
ab = raw_input('Choose either A or B > ')
input()
expects a Python expression as input; according to the Python documentation, it is equivalent to eval(raw_input(prompt))
. Just use raw_input()
, along with the other suggestions posted here.
try:
inp = raw_input # Python 2.x
except NameError:
inp = input # Python 3.x
def chooseOneOf(msg, options, prompt=': '):
if prompt:
msg += prompt
options = set([str(opt).lower() for opt in options])
while True:
i = inp(msg).strip().lower()
if i in options:
return i
ab = chooseOneOf('Choose either A or B', "ab")
lr = chooseOneOf('Left or right', ('left','right'))
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