How can I get a list of all classes within current module in Python?
I've seen plenty of examples of people extracting all of the classes from a module, usually something like:
# foo.py
class Foo:
pass
# test.py
import inspect
import foo
for name, obj in inspect.getmembers(foo):
if inspect.isclass(obj):
print obj
Awesome.
But I can't find out how to get all of the classes from the current module.
# foo.py
import inspect
class Foo:
pass
def print_classes():
for name, obj in inspect.getmembers(???): # what do I do here?
if inspect.isclass(开发者_高级运维obj):
print obj
# test.py
import foo
foo.print_classes()
This is probably something really obvious, but I haven't been able to find anything. Can anyone help me out?
Try this:
import sys
current_module = sys.modules[__name__]
In your context:
import sys, inspect
def print_classes():
for name, obj in inspect.getmembers(sys.modules[__name__]):
if inspect.isclass(obj):
print(obj)
And even better:
clsmembers = inspect.getmembers(sys.modules[__name__], inspect.isclass)
Because inspect.getmembers()
takes a predicate.
I don't know if there's a 'proper' way to do it, but your snippet is on the right track: just add import foo
to foo.py, do inspect.getmembers(foo)
, and it should work fine.
What about
g = globals().copy()
for name, obj in g.iteritems():
?
I was able to get all I needed from the dir
built in plus getattr
.
# Works on pretty much everything, but be mindful that
# you get lists of strings back
print dir(myproject)
print dir(myproject.mymodule)
print dir(myproject.mymodule.myfile)
print dir(myproject.mymodule.myfile.myclass)
# But, the string names can be resolved with getattr, (as seen below)
Though, it does come out looking like a hairball:
def list_supported_platforms():
"""
List supported platforms (to match sys.platform)
@Retirms:
list str: platform names
"""
return list(itertools.chain(
*list(
# Get the class's constant
getattr(
# Get the module's first class, which we wrote
getattr(
# Get the module
getattr(platforms, item),
dir(
getattr(platforms, item)
)[0]
),
'SYS_PLATFORMS'
)
# For each include in platforms/__init__.py
for item in dir(platforms)
# Ignore magic, ourselves (index.py) and a base class.
if not item.startswith('__') and item not in ['index', 'base']
)
))
import pyclbr
print(pyclbr.readmodule(__name__).keys())
Note that the stdlib's Python class browser module uses static source analysis, so it only works for modules that are backed by a real .py
file.
If you want to have all the classes, that belong to the current module, you could use this :
import sys, inspect
def print_classes():
is_class_member = lambda member: inspect.isclass(member) and member.__module__ == __name__
clsmembers = inspect.getmembers(sys.modules[__name__], is_class_member)
If you use Nadia's answer and you were importing other classes on your module, that classes will be being imported too.
So that's why member.__module__ == __name__
is being added to the predicate used on is_class_member
. This statement checks that the class really belongs to the module.
A predicate is a function (callable), that returns a boolean value.
This is the line that I use to get all of the classes that have been defined in the current module (ie not imported). It's a little long according to PEP-8 but you can change it as you see fit.
import sys
import inspect
classes = [name for name, obj in inspect.getmembers(sys.modules[__name__], inspect.isclass)
if obj.__module__ is __name__]
This gives you a list of the class names. If you want the class objects themselves just keep obj instead.
classes = [obj for name, obj in inspect.getmembers(sys.modules[__name__], inspect.isclass)
if obj.__module__ is __name__]
This is has been more useful in my experience.
Another solution which works in Python 2 and 3:
#foo.py
import sys
class Foo(object):
pass
def print_classes():
current_module = sys.modules[__name__]
for key in dir(current_module):
if isinstance( getattr(current_module, key), type ):
print(key)
# test.py
import foo
foo.print_classes()
I think that you can do something like this.
class custom(object):
__custom__ = True
class Alpha(custom):
something = 3
def GetClasses():
return [x for x in globals() if hasattr(globals()[str(x)], '__custom__')]
print(GetClasses())`
if you need own classes
I frequently find myself writing command line utilities wherein the first argument is meant to refer to one of many different classes. For example ./something.py feature command —-arguments
, where Feature
is a class and command
is a method on that class. Here's a base class that makes this easy.
The assumption is that this base class resides in a directory alongside all of its subclasses. You can then call ArgBaseClass(foo = bar).load_subclasses()
which will return a dictionary. For example, if the directory looks like this:
- arg_base_class.py
- feature.py
Assuming feature.py
implements class Feature(ArgBaseClass)
, then the above invocation of load_subclasses
will return { 'feature' : <Feature object> }
. The same kwargs
(foo = bar
) will be passed into the Feature
class.
#!/usr/bin/env python3
import os, pkgutil, importlib, inspect
class ArgBaseClass():
# Assign all keyword arguments as properties on self, and keep the kwargs for later.
def __init__(self, **kwargs):
self._kwargs = kwargs
for (k, v) in kwargs.items():
setattr(self, k, v)
ms = inspect.getmembers(self, predicate=inspect.ismethod)
self.methods = dict([(n, m) for (n, m) in ms if not n.startswith('_')])
# Add the names of the methods to a parser object.
def _parse_arguments(self, parser):
parser.add_argument('method', choices=list(self.methods))
return parser
# Instantiate one of each of the subclasses of this class.
def load_subclasses(self):
module_dir = os.path.dirname(__file__)
module_name = os.path.basename(os.path.normpath(module_dir))
parent_class = self.__class__
modules = {}
# Load all the modules it the package:
for (module_loader, name, ispkg) in pkgutil.iter_modules([module_dir]):
modules[name] = importlib.import_module('.' + name, module_name)
# Instantiate one of each class, passing the keyword arguments.
ret = {}
for cls in parent_class.__subclasses__():
path = cls.__module__.split('.')
ret[path[-1]] = cls(**self._kwargs)
return ret
import Foo
dir(Foo)
import collections
dir(collections)
The following can be placed at the top of the file:
def get_classes():
import inspect, sys
return dict(inspect.getmembers(
sys.modules[__name__],
lambda member: inspect.isclass(member) and member.__module__ == __name__
))
Note, this can be placed at the top of the module because we've wrapped the logic in a function definition. If you want the dictionary to exist as a top-level object you will need to place the definition at the bottom of the file to ensure all classes are included.
Go to Python Interpreter. type help ('module_name') , then press Enter. e.g. help('os') . Here, I've pasted one part of the output below:
class statvfs_result(__builtin__.object)
| statvfs_result: Result from statvfs or fstatvfs.
|
| This object may be accessed either as a tuple of
| (bsize, frsize, blocks, bfree, bavail, files, ffree, favail, flag, namemax),
| or via the attributes f_bsize, f_frsize, f_blocks, f_bfree, and so on.
|
| See os.statvfs for more information.
|
| Methods defined here:
|
| __add__(...)
| x.__add__(y) <==> x+y
|
| __contains__(...)
| x.__contains__(y) <==> y in x
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