Java simple regular expression
I want to specify a regex that finds if there are any non letter non number chars in a Str开发者_开发问答ing.
Basically I want it to accept [a-z][A-Z][0-9]
in any order any combination..i.e "2a4A44awA"
should be valid.
How can I do this?
Instead of:
[a-z][A-Z][0-9]
Match with:
[a-zA-Z0-9]+
From the API:
Greedy quantifiers
X? X, once or not at all
X* X, zero or more times
X+ X, one or more times
X{n} X, exactly n times
X{n,} X, at least n times
X{n,m} X, at least n but not more than m times
String s = ".... ;
System.out.println(s.matches(".*[^a-zA-z0-9].*"));
returns true if illegal character is present.
Edit: But the first answer from jzd is better:
s.matches("[a-zA-Z0-9]+");
Returns true if illegal character not present, ie the string is good.
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